There’s are ratio which would be 8/10. 12/x should equally 8/10. So it would be 14 tiles long.
Answer:4y
Step-by-step explanation:
The key features of
polynomials are the vertex, axis of symmetry, x and y intercepts.
<span>1.
</span>The degree will help you find the end behavior.
<span>2. </span>The vertex shows you where it changes concavity.
<span>3. </span>X and y intercepts give you a couple of points
of reference.
<span>4. </span>Axis of symmetry is only applicable to even
degree polynomials.
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
Hey there!!
Fill in the blanks :-
⇒ First graph the line. Locate the <u>value of x </u>on the x-axis. Draw a vertical line from <u>point plotted on the x-axis </u>to the graph of the function and a horizontal line segment from the graph of the function to the y-axis.
<em>Find the value of f(x) when x is -2. </em>
Remember :- <u><em>f(x) is basically the y-value. It is just denoted as _f(x), it stands for function of x. Which means, the value of y, depends upon the value of x or the function of x. </em></u>
Given : x = - 2
Plugging in the values :
... 
... 
... 
The last fill in the blank :
The value of y on the y-axis is the value of the function. Therefore, the value of f(x) is <u>-7 </u>when x is -2.
Hope it helps!!
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
