Subtract 7 both sides
Subtract 9x both side
They cancel out
At the end you divide it
I don’t have access to paper right now sorry
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
__
We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
Step-by-step explanation:
Y= x - 2. Y = 3x + 5
Putting value of y
x - 2 = 3x + 5
-2 - 5 = 3x - x
-7 = 2x
-7/2 = x
Putting value of x
Y = 3(-7/2) + 5
Y = - 10.5 + 5
Y = - 5.5
Answer: The answer is C) y= 2/3x-3
Step-by-step explanation:
i figure it out
It might be 2.5 but I could be wrong
