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ANEK [815]
3 years ago
10

Evaluate f (x) = 2x4 – 4x3 – 11x2 3x – 6 for x = –2. f (–2) =

Mathematics
2 answers:
Musya8 [376]3 years ago
8 0
Hello,

After decrypting the question:

f(x)=2x^4-4x^3-11x^2+3x-6

f(-2)=2(-2)^4-4(-2)^3-11(-2)^2+3*(-2)-6=2*16+32-44-6-6=8

Art [367]3 years ago
5 0

Answer:

The value of f(x) is 8 at x=-2.

Step-by-step explanation:

The given function is

f(x)=2x^4-4x^3-11x^2+3x-6

We have to find the value of function at x=-2.

Substitute x=-2 in the given function.

f(-2)=2(-2)^4-4(-2)^3-11(-2)^2+3(-2)-6

f(-2)=32+32-44-6-6

f(-2)=64-56

f(-2)=8

Therefore the value of f(x) is 8 at x=-2.

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jefferson park sits on one square city block 300 feet on each side. Sidewalks join opposite corners. About how long is each diag
wolverine [178]
About 425 feet, a^2*b^2=c^2, so 90,000+90,000=180,000 and the square root of 180,000 is about 424.
5 0
3 years ago
A, B, and C are collinear, and B is between A and C. The ratio of AB to BC is 3 : 1.
S_A_V [24]

Coordinates of point C: (1,-1)

Step-by-step explanation:

In this problem, A, B and C are collinear, and B is between A and C.

The ratio AB : BC is 3 : 1.

This means that we can write the following two equations:

x_B-x_A = 3(x_C-x_B)\\y_B-y_A=3(y_X-y_B)

where:

(x_A,y_A)=(-7,3) are the coordinates of point A

(x_B,y_B)=(-1,0) are the coordinates of point B

(x_C,y_C) are the coordinates of point C

Solving the equation for x_C,

x_C = x_B + \frac{x_B-x_A}{3}=-1+\frac{-1-(-7)}{3}=1

Solving the equation for y_C,

y_C=y_B + \frac{y_B-y_A}{3}=0+\frac{0-3}{3}=-1

So, the coordinates of point C are

C(-1,1)

Learn more about how to divide segments:

brainly.com/question/3269852

brainly.com/question/11280112

#LearnwithBrainly

4 0
3 years ago
The table below shows two equations:
NikAS [45]

Answer:

I think it is the last one

Step-by-step explanation:

5 0
3 years ago
Find the number of 4-digit numbers that contain exactly two even and two odd digits.
Dvinal [7]

Answer:

2,435

Step-by-step explanation:

find two even and two odd

7 0
3 years ago
100 PTS!! PLEASE HELP! OVER DUE
Reika [66]

Answer:

-\frac{1}{2} \vec {c}

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because \frac{4}{4}=1=\frac{-2}{-2}

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector.  This means that there is some number "k", such that k \vec{c} = \vec {d}, or equivalently, kc_x=d_x and kc_y=d_y.

If kc_x=d_x and kc_y=d_y, we just need to substitute known values and solve for k:

kc_x=d_x\\k(4)=(-2)\\k=\dfrac{-2}{4}\\k=-\frac{1}{2}

Double checking that k works for the y-coordinates as well:

kc_y=d_y

(-\frac{1}{2}) (4)    ?    (-2)

-2=-2 \text{ } \checkmark

So, -\frac{1}{2} \vec {c} = \vec {d}

6 0
2 years ago
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