Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
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Answer:
4k-6
Step-by-step explanation:

Answer:
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Answer: The numbers are 14, 16 and 18.
Step-by-step explanation: First thing to note is that consecutive even numbers have a difference of 2 units between every two terms. That is, if the first number is a, the next would be a + 2, and the next would be a + 4, and so on.
Therefore the three consecutive even numbers shall be a, a + 2, and a + 4.
Our equation now becomes;
a + a + 2 + a + 4 = 48
3a + 6 = 48
Subtract 6 from both sides of the equation
3a = 42
Divide both sides of the equation by 3
a = 14
Therefore, the numbers are 14, 16 and 18.