Answer:
Please check the explanation.
Step-by-step explanation:
Given the vector
v = 6i + 2√3j
The Magnitude of a vector:
![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Bab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D)
The Direction of a vector:
tan Ф = y/x
y=2√3
x = 6
tan Ф = y/x
= 2√3 / 6
= √3 / 3
Answer:
1/3
Step-by-step explanation:
We can solve using algebra: let x be the unknown number.
so 11/3 ÷ x = 11.
Solving:
11/3 = 11x.
x = 11/3 ÷11 = 1/3
You can also check the answer by going:
11/3 ÷ 1/3 = 11/3 x 3/1 = 33/3 = 11 (using fraction rules for multiplying and dividing ie. to divide by a fraction we multiple by it's reciprocal, and to multiply by a fraction, we multiple the numerators and the denominators).
I believe the correct awnser is c let me know !
Answer:
y=1x+-3
Step-by-step explanation:
using rise over run we can see that we go up one from a point and over 1 from a point making our slope 1. then you you find the y-intercept and here that is very easy because we can clearly see the line pass through -3 on the y axis. the just substitute in your values to get y=1x+-3
A= 0.25 or 1/4
Hope this helps:)
