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Mila [183]
3 years ago
11

Will give Brainly please help

Mathematics
2 answers:
Lunna [17]3 years ago
6 0

Answer:

it is B) 95

Step-by-step explanation:

supplementary mean equals to 180. in a triangle problem all the angles should add up to 180. so you take 180 and subtract the number you already have which is 85 and you get 95

s2008m [1.1K]3 years ago
3 0

Answer:

B. 95º

Step-by-step explanation:

Supplementary angles are ones that add up to 180º.

So if angle 1 is 85º, then the equation would be:

(x-the measure of angle 2)

X + 85 = 180

Solve for x:

X + (85-85) = 180-85

X = 95.

Hope this helps! Have a great day!

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50 POINTS, I NEED IT QUICK PLSS
olga nikolaevna [1]

The thing that's wrong with the equation is that 2 shouldn't be multiplied by 4 but should have been added.

<h3>How to illustrate the information?</h3>

From the information given, it can be seen that the equation is:

(3x²)(-2x⁴) = 3(-2)x² × x⁴ = 6x^8

Based on the information above, this calculation is incorrect. The correct calculation will be:

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brainly.com/question/2972832

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7 0
2 years ago
ABCD is a rectangle. Its diagonals are AC and BD. If AC = 12cm, then BD = _______cm
defon

Answer:

BD = 12\ cm

Step-by-step explanation:

Given

Shape: Rectangle

Diagonals: AC and BD

AC = 12\ cm

Required

Determine BD

From the question, we understand that the shape is a rectangle and its diagonals are AC and BD

Every rectangle has 2 diagonals, both of which are equal.

This implies that:

BD = AC

Recall that:

AC = 12\ cm

Hence,

BD = 12\ cm

8 0
3 years ago
Which Quadrant contains the point named by (4,-8)
ELEN [110]
The quadrants the point (4.-8) is in is the fourth quadrants
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Read 2 more answers
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geniusboy [140]

Answer:

b. y=sec(x/3) and y=-1

Step-by-step explanation:

sec(x/3) + 4 > 2 − sec(x/3)

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sec(x/3) > -1

Graph y = sec(x/3) and y = -1.

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3 years ago
HELP MEEEE!!!<br><br> which of these graphs do not represent constant rates of change ?
Ganezh [65]

Answer:

Hello! Your answer would be below!

Step-by-step explanation:

Graph B)

Hope I helped! Ask me anything if you have questions!

3 0
3 years ago
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