Using the monthly payments formula, it is found that a car with a value of at most $25,293.
<h3>What is the monthly payment formula?</h3>
It is given by:

In which:
- n is the number of payments.
In this problem, we have that the parameters are given as follows:
A = 400, n = 70, r = 0.035.
Hence:
r/12 = 0.035/12 = 0.002917.
Then we have to solve for P to find the maximum value of the car.


![P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B400%5B%281.002917%29%5E%7B70%7D-1%5D%7D%7B0.002917%281.002917%29%5E%7B70%7D%7D)
P = $25,293.
More can be learned about the monthly payments formula at brainly.com/question/26267630
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Answer:
g = 23/16
Step-by-step explanation:
3/16 = (-5/4) + g
g = 5/4 + 3/16
g = 23/16
Answer:
<em> </em><em>a </em><em>+</em><em> </em><em>5</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>c</em>
Step-by-step explanation:
here's your solution
=> 3a + 4b + 5c +(-2a) + b
=> solve for like term
=> 3a - 2a + 4b + b + 5c
=> a + 5b + 5c
hope it helps