Answer:
m=2 I think thats the right answer
Given:
The image of a lens crosses the x-axis at –2 and 3.
The point (–1, 2) is also on the parabola.
To find:
The equation that can be used to model the image of the lens.
Solution:
If the graph of polynomial intersect the x-axis at c, then (x-c) is a factor of the polynomial.
It is given that the image of a lens crosses the x-axis at –2 and 3. It means (x+2) and (x-3) are factors of the function.
So, the equation of the parabola is:
...(i)
Where, k is a constant.
It is given that the point (–1, 2) is also on the parabola. It means the equation of the parabola must be satisfy by the point (-1,2).
Putting
in (i), we get



Divide both sides by -4.


Putting
in (i), we get

Therefore, the required equation of the parabola is
.
Note: All options are incorrect.
1. 3cm ,M is the midpoint
2. ND , 3cm,
3. BC, According to the diagram
4. 12 Cm
77 times 100 is 7,700. So your answer is 7,700
Answer:
<h2>137°</h2>
Step-by-step explanation:
The pentagon RSTYZ is a regular polygon. Therefore all angles are congruent.
If m∠RST = 108°, then m∠STY = 108°.
We have the equation:
m∠UTY + m∠STY + m∠STU = 360°.
Substitute m∠STY = 108° and m∠UTY = 115°.
115° + 108° + m∠STU = 360°
223° + m∠STU = 360° <em>subtract 223° from both sides</em>
m∠STU = 137°