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zysi [14]
3 years ago
13

How do you know when you have found the prime factorization of a number?

Mathematics
2 answers:
SashulF [63]3 years ago
5 0
You've found the prime factorization when all of your factors are prime. They can't be divided into any smaller factors.
guapka [62]3 years ago
3 0
You know because all the factors are prime, none of them are one, and they multiply to make said number.

Hope this helps :)<span />
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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
Solve the system by adding or subtracting.
irakobra [83]
The answer is (4,-7) :)
3 0
2 years ago
Read 2 more answers
13 - 3/2<br> Pls give an explanation
postnew [5]

13-3/2 you need to make a common denominator, so

26/2-3/2 then subtract the numerators, the denominator remains.

23/2 now simplify the fraction

11½ this is because 22/2+1/2=23/2, and 22/2=11, so 11+1/2 or 11½

7 0
3 years ago
If a^2 + b^2=c^2 then the triangle is a right triangle.
NARA [144]

Answer:

False

Step-by-step explanation:

Measurements are too long on the A leg and B leg for it to be connected by a 12 in leg.

4 0
3 years ago
Jay jogged 2/3 mile in 1/12 hour. What was his speed in mile per hour?
Dennis_Churaev [7]

Answer:

The speed is 2 miles per hour

4 0
3 years ago
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