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3 years ago

Could someone help me step by step with this question?

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

$\frac{2}{3}(9+x)=-5(4-x) \\ \\ 3*\frac{2}{3}(9+x)=3*[-5(4-x)] \\ \\ 2(9+x)=-15(4-x) \\ \\ 18+2x=-60+15x \\ \\ -13x=-78 \\ \\ \cfrac{-13x}{-13} = \cfrac{-78}{-13} \\ \\ x=6$

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What is the area of the following circle r=2

denpristay [2]

Answer:

12.57

Step-by-step explanation:

$\pi r^2\\\pi (2)^2\\=12.57$

8 0

3 years ago

P − 4.8 less than or = to 6.

docker41 [41]

-4.8 is less than 6

if its just regular 4.8 ( not negative, it'd still be less than )

[If the six is negative than it would be greater than.]

4 0

4 years ago

Read 2 more answers

Simplify; 1/x^2+5x+6 + 1/x^2+3x+2 pls I need a step by step solution urgently

ikadub [295]

Answer:

The simplest form of $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ is $\frac{2}{(x+1)(x+3)}$

Step-by-step explanation:

To add two algebraic fractions do these steps

Factorize each denominator
Simplify each fraction to its lowest term
Find the LCM of the two denominators
Divide LCM by each denominator and multiply the numerators by its corresponding quotients
Add the two fraction and simplify the last answer

To simplify $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$

Factorize each denominator

∵ The denominator of the first fraction is x² + 5x + 6

∵ x² = (x)(x)

∵ 6 = (2)(3)

∵ (2)(x) + (3)(x) = 5x ⇒ middle term

∴ x² + 5x + 6 = (x + 2)(x + 3)

∵ The denominator of the second fraction is x² + 3x + 2

∵ x² = (x)(x)

∵ 2 = (2)(1)

∵ (2)(x) + (1)(x) = 3x ⇒ middle term

∴ x² + 3x + 2 = (x + 2)(x + 1)

Find the LCM of the two denominators

∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)

- LCM is all the different factors multiplied together

∴ LCM of them is (x + 1)(x + 2)(x + 3)

- Divide LCM by each denominator

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)

- Multiply the numerator of the first fraction by (x + 1)

∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)

- Multiply the numerator of the second fraction by (x + 3)

∴ $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ = $\frac{x+1}{(x+1)(x+2)(x+3)}+\frac{x+3}{(x+1)(x+2)(x+3)}$

- Add the numerators and write the answer as a single fraction

∴ $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ = $\frac{2x+4}{(x+1)(x+2)(x+3)}$

- Factorize the numerator by taking 2 as a common factor

∵ 2x + 4 = 2(x + 2)

∴ $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ = $\frac{2(x+2)}{(x+1)(x+2)(x+3)}$

- Simplify the fraction by dividing up and down by (x + 2)

∴ $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ = $\frac{2}{(x+1)(x+3)}$

The simplest form of $\frac{1}{x^{2}+5x+6}+\frac{1}{x^{2}+3x+2}$ is $\frac{2}{(x+1)(x+3)}$

5 0

3 years ago

457Δ is a 4-digit number with one of its digits represented by Δ. 457Δ is divisible by 3. Which of these is also a number divisi

dexar [7]

Answer:

by divisibility rule of 3 for a no. to be divisible by 3 there is necessary condition that sum of all digit is divisible by 3.

so ans is 2 (smallest digit)

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3 years ago

Mr. Chase is having a party for his teachers. If the pizzeria cuts their pies into eight slices and each teacher is eating 1/8 o

Ivanshal [37]

6 pies.

If 8 teachers finish one whole pie, and they need to feed 47, then they need 6 pies with 8 slices each aka 48 slices total, there will be one slice leftover for the principal :D

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2 years ago