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3 years ago

Could someone help me step by step with this question?

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

$\frac{2}{3}(9+x)=-5(4-x) \\ \\ 3*\frac{2}{3}(9+x)=3*[-5(4-x)] \\ \\ 2(9+x)=-15(4-x) \\ \\ 18+2x=-60+15x \\ \\ -13x=-78 \\ \\ \cfrac{-13x}{-13} = \cfrac{-78}{-13} \\ \\ x=6$

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An experienced cashier at a grocery store takes 2 seconds to scan each item and 40 seconds to process the customer's payment. 1)

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The correct option is D) 43 items.

Step-by-step explanation:

As we know that total given time is ,

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3 years ago

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2 years ago

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

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3 years ago

Read 2 more answers