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hoa [83]
3 years ago
8

HELP! Determine the equation of the exponential function with a common ratio of 2, a horizontal asymptote at y = 4, and passing

through the point (2, 10).
Mathematics
1 answer:
julsineya [31]3 years ago
4 0

Answer:

\bold{y=1.5\times 2^x+4}

Step-by-step explanation:

Equation for an exponential function is given as following:

y=ab^x+c

Where <em>b</em> is the common ratio and  

<em>c</em> is the horizontal asymptote (y value)

<em>a</em> is the coefficient of exponential term of x

(x,y) are the points on the function.

Here, we are given that:

Common ratio, b = 2

Horizontal asymptote at y, c = 4

So, the equation becomes (let us put the values of <em>b</em> and <em>c</em>):

y=a\times 2^x+4

We need the value of <em>a. </em>Let us put value of (x,y) as (2,10).

10=a\times 2^2+4\\\Rightarrow a\times 4 =10-4 =6\\\Rightarrow a =\dfrac{6}{4} =\bold{1.5}

So, the final equation of the exponential function is:

\bold{y=1.5\times 2^x+4}

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