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3 years ago

7

A plane took 3 h 33 min to finish a journey. If the distance of the journey was 2840 miles, at what average speed did the plane

travel?

1 answer:

Elina [12.6K]3 years ago

8 0

Answer:

800mph

Step-by-step explanation:

Step one

Given data

time taken= 3 h 33 min

= 3.55 hours

distance = 2840 miles

Step two:

from speed= distance/time

substitute

speed= 2840/3.55

speed= 800mph

Hence the speed is 800mph

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harkovskaia [24]

Answer:

A) speed = 10.5 miles per hour

B) Time taken by him = 1.714 hours

C) Distance = 10.5 mph × 7 hours = 73.5 miles

Step-by-step explanation:

Given as :

The distance cover by David = $\frac{21}{4}$ miles = 5.25 miles

The time taken by David = $\frac{1}{2}$ hours = 0.5 hours

Let the speed = x mile per hour

So, Distance = Speed × Time

A)or, Speed = $\frac{Distance}{Time}$

Or, Speed = $\frac{5.25}{0.5}$

∴ speed = 10.5 miles per hour

<u>B) Again The Distance cover by him = 18 miles</u>

SO, with speed 10.5 miles per hour

The Time taken by him = $\frac{Distance}{speed}$ hours

Or, Time taken by him = $\frac{18}{10.5}$ hours

∴ Time taken by him = 1.714 hours

<u>C) Again the Time taken by him = 7 hours </u>

So, Distance cover by him with speed 10.5 mph

Or, Distance = 10.5 mph × 7 hours = 73.5 miles

A) speed = 10.5 miles per hour

B) Time taken by him = 1.714 hours

C) Distance = 10.5 mph × 7 hours = 73.5 miles Answes

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yarga [219]

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