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3 years ago

In the formula a^2 + b^2 = c^2 , what is the value of a^2 ?

Mathematics

2 answers:

maksim [4K]3 years ago

6 0

The answer would be A. c^2 – b^2
If you need more help just ask :)

professor190 [17]3 years ago

3 0

a^2 + b^2 = c^2 ; value of a^2?

Subtract b^2 to both sides

a^2 + b^2 - b^2 = c^2 - b^2

Simplify

a^2 = c^2 - b^2

Answer is A. c^2 – b^2

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Can someone help me with this? thank you!

Vedmedyk [2.9K]

Answer:

V = 240 $cm^{3}$

Step-by-step explanation:

To find the volume of a rectangular prism use this equation:

V = l*w*h

l = length (20 cm)

w = width (4 cm)

h = height (3 cm)

Plug all these values into the equation and solve:

V = (20 cm)(4 cm)(3 cm)

V = (80 $cm^{2}$ )(3 cm)

V = 240 $cm^{3}$

Therefore, the volume of the rectangular prism is 240 $cm^{3}$ .

I hope this helps! Good luck!

8 0

2 years ago

What is the measure of A? And B

sladkih [1.3K]

Answer:

A = 72°

B = 108°

Step-by-step explanation:

5y - 3 = 3y + 27

5y - 3y = 27 + 3

2y = 30

y = 30/2

y = 15

A = 5y - 3

A = 5(15) - 3

A = 75 - 3

A = 72°

A + B = 180°

72° + B = 180°

B = 180° - 72°

B = 108°

7 0

2 years ago

Read 2 more answers

at a softball game you can get a bratwurst for $4.50. you have $18 to spend. write and solve an inequality to determine the numb

babunello [35]

You can only buy 4 bratwursts.

4 0

3 years ago

Multiply. What is the value of the second partial product 27x108

jeyben [28]

<h2>Answer:</h2><h2>The partial products of (27) (108) are 216 , 0 , 27.</h2>

Step-by-step explanation:

To find the value of the second partial product 27x108,

Here the multiplicand = 27

The multiplier = 108

The partial products of the multiplication are :

(27) (8) = 0 2 1 6

(27) (0) = 0 0 0

(27) (1) = 2 7

Adding the terms, we get 2916.

The partial products are 216 , 0 , 27.

5 0

3 years ago

Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.

disa [49]

Answer:

The solutions $x^4-5x^2-36=0$ are $x=3,\:x=-3,\:x=2i,\:x=-2i$ and the x-intercepts of $y=x^4-5x^2-36$ are $x=3,\:x=-3$

Step-by-step explanation:

Finding the solutions to $x^4-5x^2-36$ means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with $u=x^2$ and $u^2=x^4$

$u^2-5u-36=0$

Solve by factoring

$\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)$

$\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)$

$\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)$

$u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)$

$\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)$

$u^2-5u-36=\left(u+4\right)\left(u-9\right)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

$\:u=-4,\:u=9$

Substitute back $u=x^2$ , solve for x

$x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)$

Apply the difference of squares formula

$x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)$

$(x-3)(x+3)(x^2+4)=0$

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

$\:x=3,\:x=-3,\:x=2i,\:x=-2i$

Because two of the solutions are complex roots the only x-intercepts are $x=3,\:x=-3$

3 0

3 years ago