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3 years ago

Did I do this right too?

Mathematics

1 answer:

Tcecarenko [31]3 years ago

7 0

For the second example, x should be 25, not 80.

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Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va

Nat2105 [25]

Answer:

(a square +7a+12) ÷(a+3)

5 0

2 years ago

If 57 is added to a number, it will be 4 times as large as it was originally. Find the number.

Sonja [21]

Answer:

Step-by-step explanation:

X will refer to the number.

X+57( the number added to the original.)=4x. (x time 4)

X+57=4x.

Subtract x from both sides to get the variable on one side.

(X+57)-x =(4x)-x

57=3x. You would then divide by 3 on both sides to again get integer isolated.

57/3=3/3x.

57/3=19. 3/3=1.

19=x.

6 0

3 years ago

Find the total surface area of this triangular prism.

Irina18 [472]

Answer:

not sure but i think its 425 cm

Step-by-step explanation:

for the square i dont know

how its called in english the surface is 25×10= 250cm

and for the triangle its (25×14):2 = 175cm

so 175 + 250= 425cm

4 0

2 years ago

What is the volume of the triangular prism below? 7 yd 18 yd 12 yd

Citrus2011 [14]

Step-by-step explanation:

V = 1/2 a x c x h

1/2 * 7*12*18 = 756 yd ^3

7 0

3 years ago

1. Writing an equation for an exponential function by

Naya [18.7K]

Answer: 1) $t(n)=0.6(2)^n$

2) $f(x)=10(5)^x$

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

$t(n) = ab^n$ ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

By equation (1),

$0.6 = a(b)^0\implies 0.6 = a$

Hence the function that shows the given situation,

$t(n) = 0.6 b^n$ -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

Thus, at n = 1, t(1) = 1.2

By equation (2),

$1.2 = 0.6 b^1\implies 2 = b$

Thus, the complete function is,

$t(n) = 0.6 (2)^n$

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = ab^x$ ---------(1)

For f(x) = 2, x = -1

By equation (1),

$2= ab^{-1}$ ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

$\frac{2}{5}= a(b)^{-2}$

$\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}$

$\implies \frac{2}{5}=\frac{2}{b}$

$\implies 2b=10$

$\implies b = 5$

By substituting this value in equation (2),

We get, a = 10

Hence, from equation (1), the function that is passing through the points (-2, 2/5) and (-1,2),

$f(x) = 10(5)^x$

5 0

3 years ago