Answer:
1) binomial
2) monomial
Step-by-step explanation:
mono-think one
bi-think two
tri-think thee
poly-1 or more
So 1 goes with binomial
and 2 goes with monomial
See if you can figure out 3 and 4
I can check them.
The 12 sided cube with the numbers 1 to 12 is rolled. That means it can land on any number from 1 to 12. The number of total possible outcomes is 12. The number of favourable outcomes, that is, the number of times the cube lands on a number than 4 is 12-1=11.
Probability=Number of favourable outcomes/number of total possible outcomes
= 11/12
= 0.92
I really hope this helps! And pls mark it as brainliest.
Answer:
See below
Step-by-step explanation:
B) The correlation coefficient is
, which can be determined by plugging the data into a TI-84 calculator.
C) A correlation coefficient of
indicates that the correlation between the independent and dependent variable (x and y in this case) is moderately strong with a positive correlation. The closer
is to 1, the stronger the positive correlation. The closer
is to -1, the stronger the negative correlation. If
is closer to 0, then there's no correlation.
Answer:
Some of the applications for exponential functions are:
1. model populations
2. carbon date artifacts
3. compound interest
hope this helps!
Both fractions have the same denominator so it's going to be easy. First set up your equation:
![3 \frac{3}{5} + 9 \frac{3}{5}](https://tex.z-dn.net/?f=%203%20%5Cfrac%7B3%7D%7B5%7D%20%2B%209%20%5Cfrac%7B3%7D%7B5%7D%20%20)
Add the whole numbers:
![3 + 9 = 12](https://tex.z-dn.net/?f=%203%20%2B%209%20%3D%2012%20)
Now add the fractions:
![\frac{3}{5} + \frac{3}{5} = \frac{6}{5}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B5%7D%20%2B%20%5Cfrac%7B3%7D%7B5%7D%20%3D%20%5Cfrac%7B6%7D%7B5%7D%20%20%20)
add both together:
![12 + \frac{6}{5} = 12 \frac{6}{5}](https://tex.z-dn.net/?f=%2012%20%2B%20%5Cfrac%7B6%7D%7B5%7D%20%3D%2012%20%5Cfrac%7B6%7D%7B5%7D%20%20%20%20)
is an improper fraction so change it:
![12 \frac{6}{5} = 13 \frac{1}{5}](https://tex.z-dn.net/?f=%2012%20%5Cfrac%7B6%7D%7B5%7D%20%3D%2013%20%5Cfrac%7B1%7D%7B5%7D%20%20%20)
Since 6 is one more than 5, add 1 to the whole number and subtract the numerator and denominator(6 - 5 = 1) and make the remaining the new numerator. That leaves you with ![13 \frac{1}{5}](https://tex.z-dn.net/?f=%2013%20%5Cfrac%7B1%7D%7B5%7D%20%20)
Your answer is ![13 \frac{1}{5}](https://tex.z-dn.net/?f=%2013%20%5Cfrac%7B1%7D%7B5%7D%20%20)