Graph the function y= 3/2x^3. Plot five points on the graph of the function: one point with x = 0, two points with negative x-va
1 answer:
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Answer:
See below
Step-by-step explanation:
Use 5 for "x" or "a number" and see if the inequality is true.
a) =3 < 5+11 < 2 . . . . false. 16 is not less than 2
b) 7·5 ≥ 35 or 4·5 < -12 . . . . true. 35 = 35
c) -7 + 2·5 = 3 is at most 2 . . . . false. 3 > 2
d) 5·5 +3 = 28 is between 2 and 30 . . . . true.
Answer:
<h2>AC = 36.01</h2>Step-by-step explanation:
Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.
From ΔADB, AB² = AD²+BD²
Given AB = 24 and AD = 16
BD² = AB² - AD²
BD² = 24²-16²
BD² = 576-256
BD² = 320
BD =
BD = 17.9
from ΔABC, AC² = AB²+BC²
SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;
(AD+DC)² = AB²+ (BD² + DC²)
Given AD = 16, AB = 24 and BD = 17.9, on substituting
(16+DC)² = 24²+17.9²+ DC²
256+32DC+DC² = 24²+17.9²+ DC²
256+32DC = 24²+17.9²
32DC = 24²+17.9² - 256
32DC = 640.41
DC =
DC = 20.01
Remember that AC = AD+DC
AC = 16+20.01
AC = 36.01