if the coordinate of one end of a diameter of the circle having equation x^2+y^2+4x-6y+8=0 is (0,2) then find the coordinate of
the other end of the diameter
1 answer:
Answer: (-4, 4)
<u>Step-by-step explanation:</u>
Given: x² + 4x + y² - 6y = -8
Complete the square: x² + 4x <u>+ 4</u> + y² - 6y <u>+ 9</u> = -8 <u>+ 4</u> <u>+ 9</u>
→ (x + 2)² + (y - 3)² = 5
Center: (-2, 3)
Since one end point of the circle is (0, 2) and the other end point must pass through endpoint (0, 2) and the center (-2, 3), find the slope ...
m = down 1 and right 2
The other endpoint will be: UP 1 and LEFT 2 from the center
→ (-2 <u>- 2</u>, 3 <u>+ 1</u>) = (-4, 4)
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