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Alina [70]
3 years ago
7

if the coordinate of one end of a diameter of the circle having equation x^2+y^2+4x-6y+8=0 is (0,2) then find the coordinate of

the other end of the diameter​

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:  (-4, 4)

<u>Step-by-step explanation:</u>

Given: x² + 4x    +  y² - 6y      = -8

Complete the square:  x² + 4x <u>+ 4</u> +  y² - 6y <u>+ 9</u> = -8 <u>+ 4</u> <u>+ 9</u>

                                  →     (x + 2)²   +      (y - 3)²    =     5

Center: (-2, 3)

Since one end point of the circle is (0, 2) and the other end point must pass through endpoint (0, 2) and the center (-2, 3), find the slope ...

m = down 1 and right 2

The other endpoint will be:  UP 1 and LEFT 2 from the center

→ (-2 <u>- 2</u>, 3 <u>+ 1</u>)    =   (-4, 4)

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