11,220,000,000 is the answer for this question.
Answer:
The probability that there are 3 or less errors in 100 pages is 0.648.
Step-by-step explanation:
In the information supplied in the question it is mentioned that the errors in a textbook follow a Poisson distribution.
For the given Poisson distribution the mean is p = 0.03 errors per page.
We have to find the probability that there are three or less errors in n = 100 pages.
Let us denote the number of errors in the book by the variable x.
Since there are on an average 0.03 errors per page we can say that
the expected value is,
= E(x)
= n × p
= 100 × 0.03
= 3
Therefore the we find the probability that there are 3 or less errors on the page as
P( X ≤ 3) = P(X = 0) + P(X = 1) + P(X=2) + P(X=3)
Using the formula for Poisson distribution for P(x = X ) = 
Therefore P( X ≤ 3) = 
= 0.05 + 0.15 + 0.224 + 0.224
= 0.648
The probability that there are 3 or less errors in 100 pages is 0.648.
The answer is 11. 0.22 x 50 is 11.
Answer:


Step-by-step explanation:


Hope this helps
Answer:
9 Signs
Step-by-step explanation:
The hiking trail is 4 kilometer long.
Signs are placed at the beginning and at the end of the trail.
4km = 4000m
We can solve this using simple arithmetic progression.
- The first term,a= 0
- The common difference,d= 500.
- The last term,l= 4000.
Therefore:
Last term, l=a+(n-1)d
4000=0+500(n-1)
4000=500n-500
4000+500=500n
4500=500n
Divide both sides by 500
n=9
Therefore, there are a total of 9 signs on the entire trail.
CHECK
The signs are placed at this marks
0m,500m,1000m,1500m,2000m,2500m,3000m,3500m and 4000m