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Tasya [4]
3 years ago
8

You are running a fuel economy study. One of the cars you find are mmiles on a blue. It can travel 29 1\2 miles on a1 1\4 gallon

s of gasoline.Another car is red. It can travel 22 2\5 miles on 4\5 gallon of gasoline. What is the unit rate per gallon for each car?what car could travel the greater distance on a 2 gallon of gasoline? Simplify the answer
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0
Blue car get's 23.6mpg while Red car gets 28mpg.
On one gallon of fuel, Red car will travel 4.4 miles further than Blue car.
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HELP ME PLEASE
solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

P(t)=A(r)^t

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}

Solve for A. Simplify:

\displaystyle 2=A\Big(\frac{1}{2}\Big)^3

Simplify:

\displaystyle 2=A\Big(\frac{1}{8}\Big)

Thus, the initial mass of the sample was:

A=16\text{ mg}

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0
3 years ago
Is 4 2/3 less than negative 2
adell [148]

Answer:

no

Step-by-step explanation:

-2 is less than 4 2/3

you can check this by looking at a number line

8 0
3 years ago
Read 2 more answers
One number exceeds another by 1. the sum of the numbers is 21. what are the numbers
Cerrena [4.2K]
Try this solution:
1. if 1st number is 'x', the 2d number is 'y', then it is possible to make up the system of two equation according to the condition:
\left \{ {{x-y=1} \atop {x+y=21}} \right. \ =\ \textgreater \  \  \left \{ {{x=11} \atop {y=10}} \right.
2. one number is 11, another number is 10.
3 0
3 years ago
5n + 3/4n = 2<br> Solve for n
vovangra [49]
5n+3/4n=2
20n+3n/4=2
23n/4=2
23n=8
n=8/23
3 0
3 years ago
Read 2 more answers
What is the value of the expression 8^−2 ?
muminat
_Brainliest if helped!

1 over 64 

8^2 = 64  , 8^-2 = 1/(8^2)  = 1/64 
7 0
4 years ago
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