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Tasya [4]
3 years ago
8

You are running a fuel economy study. One of the cars you find are mmiles on a blue. It can travel 29 1\2 miles on a1 1\4 gallon

s of gasoline.Another car is red. It can travel 22 2\5 miles on 4\5 gallon of gasoline. What is the unit rate per gallon for each car?what car could travel the greater distance on a 2 gallon of gasoline? Simplify the answer
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0
Blue car get's 23.6mpg while Red car gets 28mpg.
On one gallon of fuel, Red car will travel 4.4 miles further than Blue car.
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What is inequality x - 4 ‹ 0
lesya [120]

You simply add 4 to 0.

x-4<0

x<4


3 0
3 years ago
8(2x-6)=96 solve the equation
Mandarinka [93]

Answer:

x=9

Step-by-step explanation:

8(2x-6)=96

2x-6=96/8

2x-6=12

2x=12+6

2x=18

x=18/2

x=9

7 0
3 years ago
Read 2 more answers
Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu
olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is   P(A' n B' ) = 0.8855

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A  is  P(A' n B) =0.0403

Step-by-step explanation:

From the question we are told that

   The sample size is n_s =  10000

    The number of outcome for inspector A is  n__{A}} = 742

    The number of outcome for inspector B is  n__{B}} = 745

     The number of joints judged defective by both inspector is n(A u B) =  1145

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

      P(A' n B' ) =  1 - P(A u B)

Now

       P(A\ u \ B) = \frac{n(Au B)}{n_s }

substituting values

        P(A\ u \ B) = \frac{1145}{ 10 000 }

So  

      P(A' n B' ) =  1 - \frac{1145}{10 000}

     P(A' n B' ) = 0.8855

the probability that the selected joint was judged to be defective by inspector B but not by inspector A  is mathematically represented as

     P(A' n B) =  P(A \ u \ B) -P(A)

Now

        P(A) =  \frac{n__{A}}{n_s}

substituting values

       P(A) =  \frac{742}{10 000}

So

     P(A' n B) =   \frac{1145}{10 000}  - \frac{742}{10 000}

    P(A' n B) =0.0403

7 0
4 years ago
Hello, can someone please help me on solving this kind of question?
jek_recluse [69]

Answer: so i think for part a , the first term is a subscrpit 0 which is 10. Then the formula for any term in the sequence is Ao x R ^n. So R =2 so

1st term = 10 ( 2^0)= 1

2nd term = 10 (2^1) =20

3rd term = 10 (2^2)= 40

4th = 80

5th = 160

Part B

The limit as n approaches infinity for a sub n when R is 0, 1 and 2. THE LIMIT FOR R of 0, 1 and 2 is infinity.

Part C...i will have to research...sorry

Step-by-step explanation:

8 0
3 years ago
The son is 20 years younger than the father, and 5 years ago he was 5 times younger than him. How old is each of them?
Hatshy [7]

Answer:

wdym

Step-by-step explanation:

8 0
3 years ago
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