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velikii [3]
1 year ago
9

Which tool enables you to quickly take basic requirements and create a limited working system?

Mathematics
1 answer:
Butoxors [25]1 year ago
7 0

Prototyping is a tool that enables us to quickly take basic requirements and create a limited working system

<h3>What is prototyping?</h3>

Prototyping is the type of tool that is used to convert and implement the ideas of an organisation into a tangible form.

There are two major types of prototyping which includes Evolutionary and throwaway prototyping.

Therefore, Prototyping is a tool that enables us to quickly take basic requirements and create a limited working system.

Learn more about prototype here:

brainly.com/question/27896974

#SPJ4

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2 (x + 3) + 5 x = 3 (2 x minus 1)
SashulF [63]

hello

Step-by-step explanation:

3 0
3 years ago
Is 90 ten times as much as 0.9
Evgen [1.6K]
No it is 0.9x10= 9. 0.9x 100 would be 90
8 0
3 years ago
Explicit rule for sequence 5, 3, 1, -1, -3...
Phantasy [73]

Answer: 2

Step-by-step explanation: subtract by 2 every time.

4 0
3 years ago
Suppose that 4 fair coins are tossed. Let Equals The event that exactly 2 coins show tails and Equal The event that at least 2 c
faust18 [17]

Answer:

a) P ( E | F ) = 0.54545

b) P ( E | F' ) = 0

Step-by-step explanation:

Given:

- 4 Coins are tossed

- Event E exactly 2 coins shows tail

- Event F at-least two coins show tail

Find:

- Find P ( E |  F )

- Find P ( E | F prime )

Solution:

- The probability of head H and tail T = 0.5, and all events are independent

So,

                    P ( Exactly 2 T ) = ( TTHH ) + ( THHT ) + ( THTH ) + ( HTTH ) + ( HHTT) + ( HTHT)  = 6*(1/2)^4 = 0.375

                    P ( At-least 2 T ) = P ( Exactly 2 T ) + P ( Exactly 3 T ) + P ( Exactly 4 T) = 0.375 + ( HTTT) + (THTT) + (TTHT) + (TTTH) + ( TTTT)

      = 0.375 + 5*(1/2)^4 = 0.375 + 0.3125 = 0.6875

- The probabilities for each events are:

                    P ( E ) = 0.375

                    P ( F ) = 0.6875

- The Probability to get exactly two tails given that at-least 2 tails were achieved:

                    P ( E | F ) = P ( E & F ) / P ( F )

                    P ( E | F ) = 0.375 / 0.6875

                    P ( E | F ) = 0.54545

- The Probability to get exactly two tails given that less than 2 tails were achieved:

                    P ( E | F' ) = P ( E & F' ) / P ( F )

                    P ( E | F' ) = 0 / 0.6875

                    P ( E | F' ) = 0                

6 0
3 years ago
Probability of numbers divisible by 9 from numbers 1-100?
quester [9]
11
(9, 18, 27, 36, 45, 54, 63, 72, 81, 90 and 99)
Those numbers divisible by 9 are the multiple of 9; thus need to know how many multiples of 9 there are between 1 and 100:

100 ÷ 9 = 11 r 1 ÷ last multiple of 9 is 11 × 9 (= 99)
→ There are 11 - 1 + 1 = 11 numbers between 1 and 100 which are divisible by 9.

(They are 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99.)
7 0
3 years ago
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