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9 months ago

Which tool enables you to quickly take basic requirements and create a limited working system?

Mathematics

1 answer:

Butoxors [25]9 months ago

7 0

Prototyping is a tool that enables us to quickly take basic requirements and create a limited working system

<h3>What is prototyping?</h3>

Prototyping is the type of tool that is used to convert and implement the ideas of an organisation into a tangible form.

There are two major types of prototyping which includes Evolutionary and throwaway prototyping.

Therefore, Prototyping is a tool that enables us to quickly take basic requirements and create a limited working system.

Learn more about prototype here:

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Valentin [98]

Answer:

30:1

Step-by-step explanation:

90:3

90÷3=30

3÷3=1

=30:1

7 0

3 years ago

PLEASE HELP QUICKLY

iren [92.7K]

Answer:

The exponents of a start at n and decrease until they reach 0 . The exponents of b start at 0 and increase until they reach n

Step-by-step explanation:

The general formula for $(a+b)^n$ is:

$a^n + C_1a^{n-1}b + C_2a^{n-2}b^2 + ... + C_{n-1}a^2b^{n-2} + C_nab^{n-1} + b^n$

Therefore, the exponents of a start at n and decrease until they reach 0 . The exponents of b start at 0 and increase until they reach n

7 0

2 years ago

Help now fast please

Vsevolod [243]

2y64xxy43x686ex4226xe

8 0

2 years ago

Pls answer this asap

zimovet [89]

Answer:

$20.44

Step-by-step explanation:

first solve for the whole thing

10 x 6 = 60

now to the red part

2 x 1.5 = 3

now the blue

r^2 * pi = a

2^2 * 3.14

4 * 3.14 = 12.56

now add red and blue

3 + 12.56 = 15.56

now subtract that sum from the whole

60 - 15.56 = 44.44

now do

44.44 / 10 = 4.444

now see how much it would cost for the grass

4.444 * 4.60 = 20.4424 ≈ 20.44

it would cost $20.44 to get the grass reseeded

6 0

2 years ago

Read 2 more answers

In a pizza takeout restaurant, the following probability distribution was obtained for the number of toppings ordered on a large

Elis [28]

Answer:

The random variable (number of toppings ordered on a large pizza) has a mean of 1.14 and a standard deviation of 1.04.

Step-by-step explanation:

The question is incomplete:

The probability distribution is:

x P(x)

0 0.30

1 0.40

2 0.20

3 0.06

4 0.04

The mean can be calculated as:

$M=\sum p_iX_i=0.3\cdot 0+0.4\cdot 1+0.2\cdot 2+0.06\cdot 3+0.04\cdot 4\\\\M=0+0.4+0.4+0.18+0.16\\\\M=1.14$

(pi is the probability of each class, Xi is the number of topping in each class)

The standard deviation is calculated as:

$s=\sqrt{\sum p_i(X_i-M)^2}\\\\s=\sqrt{0.3(0-1.14)^2+0.4(1-1.14)^2+0.2(2-1.14)^2+0.06(3-1.14)^2+0.04(4-1.14)^2}\\\\s=\sqrt{0.3(-1.14)^2+0.4(-0.14)^2+0.2(0.86)^2+0.06(1.86)^2+0.04(2.86)^2}\\\\ s=\sqrt{0.3(1.2996)+0.4(0.0196)+0.2(0.7396)+0.06(3.4596)+0.04(8.1796)}\\\\s=\sqrt{0.3899+0.0078+0.1479+0.2076+0.3272}\\\\ s=\sqrt{ 1.0804 }\\\\s\approx 1.04$

3 0

2 years ago