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2 years ago

Help plz, i would be so happy if you did nobody's been answering my questions lately :(

Mathematics

2 answers:

Vlada [557]2 years ago

8 0

Answer:

-5x + y = 7

x+3y = 5

Step-by-step explanation:

when you graph the equations, they are parallel. as you know, solutions are the point where the lines meet. if they are parallel, it's not possible for the lines to intersect.

maria [59]2 years ago

8 0

Answer and Step-by-step explanation:

Lets solve each one and see which has solutions and which one doesn't have a solution.

__________________________________________________________

A) x + y = -6

x + y = 12

Solve for y for one of the equations, then plug it into the other equation.

y = -6 - x

x + (-6 - x) = 12 = -6 = 12 No Solution

__________________________________________________________

B) y = 2x + 5

y = -3x + 1

2x + 5 = -3x + 1

4 = - 5x

$-\frac{4}{5} =x$ Solution

_________________________________________________________ C) y = 4x - 8

y = 2x - 4

4x - 8 = 2x - 4

2x = 4

x = 2 Solution

__________________________________________________________

D) -5x + y = 7

x + 3y = 5

x = 5 - 3y

-5(5 - 3y) + y = 7

-25 + 15y + y = 7

16y = 32

y = 2 Solution

__________________________________________________________

So, A is the correct answer. Sorry for the late answer!

#teamtrees #WAP (Water And Plant)

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podryga [215]

Answer:

Matrix transformation = $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$

Vertices of the new image: P'= (5,-2), Q'= (6,-3), R'= (2,-3)

Step-by-step explanation:

Transformation by reflection will produce a new congruent object in different coordinate. Reflection to y-axis made by multiplying the x coordinate with -1 and keep the y coordinate unchanged. The matrix transformation for reflection across y-axis should be: $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ .

To find the coordinate of the vertices after transformation, you have to multiply the vertices with the matrix. The calculation of the each vertice will be:

P'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-5\\-2\end{array}\right]$ = (5,-2)

Q'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-6\\-3\end{array}\right]$ = (6,-3)

R'= $\left[\begin{array}{ccc}-1&0\\0&1\end{array}\right]$ $\left[\begin{array}{ccc}-2\\-3\end{array}\right]$ = (2,-3)

3 0

2 years ago

3x + 3y =15 and x = -3y -1

saul85 [17]

Answer:

(x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

3(-3y -1) +3y = 15

-6y = 18 . . . . . add 3 and simplify

y = -3 . . . . . . . divide by -6

x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

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daser333 [38]

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2 years ago

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nekit [7.7K]

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