Ask question

Ask question

All categories

Salsk061 [2.6K]

3 years ago

10

At midnight, the temperature was 15°C. Over the next six hours, the temperature dropped 3 degrees each hour. By noon, the temper

ature increased 12 degrees. A. What was the temperature at 6 a.m.? B. Then what was the temperature at noon?

1 answer:

Sonbull [250]3 years ago

8 0

Answer:

a)3C b)27C

Step-by-step explanation:

a) 6hours*3degrees=18 degrees

15-18=3C

b)15+12=27C

You might be interested in

What is reminder if you devide 786 to 6?

Ivenika [448]

Answer:

There is no reminder as the answer will be an integer 131.

Thank you and please rate me as brainliest as it will help me to level up

5 0

3 years ago

basically i need help trying to learn .. um ... i ... so basically what i’m asking is how.. why.... uh .. sorry i .. so overall

igor_vitrenko [27]

Can u find them ?????????????????????

4 0

3 years ago

How do I cancel this account my son graduated in 2020 and I just got charged another year?

Arte-miy333 [17]

Answer:

i'm confused

Step-by-step explanation:

5 0

3 years ago

A tourist first walked 17km with a speed of v km/h. Then he hiked 12 km uphill with the speed that was 2 km/hour less than his o

ExtremeBDS [4]

Answer: $t=\frac{17}{v}+\frac{12}{v-2}$

Step-by-step explanation:

Given: A tourist first walked 17km with a speed of v km/h.

Since $Speed=\frac{distance}{time}$

therefore, $Time=\frac{distance}{speed}$

Let $t_1$ be the time he walked with speed v.

then $t_1=\frac{17}{v}$

Also he hiked 12 km uphill with the speed that was 2 km/hour less than his original speed.

Let $t_2$ be the time he hiked 12 km,

Then $t_2=\frac{12}{v-2}$

The total time for the whole trip is given by:-

$t=t_1+t_2=$

Substitute the values of $t_1$ and $t_2$ in the equation, we get

$t=\frac{17}{v}+\frac{12}{v-2}$

4 0

3 years ago

What is the variance of the following data? If necessary, round your answer to two decimal places. 17, 13, 13, 22, 11, 20

Bond [772]

Variance is the standard deviation squared but we're not going to use that now. Let's first calculate the mean:

mean = (17+13+13+22+11+20)/6 = 16.

Now for each value, let's see how far it is from this mean. We'll square these distances and average them. That's our variance.

17 distance 1 squared = 1
13 distance 3 squared = 9
13 distance 3 squared = 9
22 distance 6 squared = 36
11 distance 5 squared = 25
20 distance 4 squared = 16

Now average these outcomes:

variance = (1+9+9+36+25+16)/6 = 16.

So the variance by coincidence is the same as the mean.

Answer C is your answer.

7 0

3 years ago