Answer:
![AB=148.76\ m](https://tex.z-dn.net/?f=AB%3D148.76%5C%20m)
Step-by-step explanation:
<u><em>The complete question in the attached figure</em></u>
we know that
The triangle PAB is a right triangle because the sum of ∠APB and ∠PAB is equal to 90 degrees
so
In the right triangle PAB
----> by SOH (opposite side divided by the hypotenuse)
substitute the given values
![sin(25^o)=\frac{AB}{352}](https://tex.z-dn.net/?f=sin%2825%5Eo%29%3D%5Cfrac%7BAB%7D%7B352%7D)
solve for AB
![AB=sin(25^o)(352)=148.76\ m](https://tex.z-dn.net/?f=AB%3Dsin%2825%5Eo%29%28352%29%3D148.76%5C%20m)
Answer:
The vertex for the function f(x) = 3(x – 2)2 + 4 is at (2, 4).
Step-by-step explanation:
Find the vertex for f(x) = 3 (x - 2)^2 + 4
f(x) = 3 (x - 2)^2 + 4 can also be written as:
y = 3 (x - 2)^2 + 4
To find critical points, first compute f'(x):
d/(dx)(3 (x - 2)^2 + 4) = 6 (x - 2):
f'(x) = 6 (x - 2)
Solve 6 (x - 2) = 0
6x - 12 = 0
6x = 12
x = 2
iI you substitute x = 2 in 3 (x - 2)^2 + 4 then you get:
y = 3 (x - 2)^2 + 4
x = 2
y = 3 (2 - 2)^2 + 4
y = 3 (0)^2 + 4
y = 3 (0) + 4
y = 4
Answer: The vertex for the function f(x) = 3(x – 2)2 + 4 is at ( 2, 4 ).
Hello,
3/5x+19−3/20x−7/35x+19−3/20x−7;
(3/5-3/20-7/35-3/20)x+(19+19-7);
(3/5-3/20-1/5-3/20)x+31;
(12-3-4-3/20)+31;
2/20x+31;
1/10x+31;
Bye :-)
Can't give you an answer without a picture of the figure.
Answer:
Step-by-step explanation:
(5/8)/(3+3/4)
(5/8)/(15/4)
(5/8)(4/15)
20/120
1/6