A quadratic with roots at 8 and 5 is f(x) = x^2 + 10x - 24
In order to find an equation given roots you can create statements that equal 0 in order to create parenthesis. For instance we know x = 8 at one point. So, we can solve that to equal 0.
x = -12 ----> add 8 from both sides
x + 12 = 0
We can do the same for the other zero.
x = 2 ----> subtract from both sides
x - 2 = 0
Now that we have both of these, we can multiply these two things together. This will give us the function we need.
f(x) = (x + 12)(x - 2)
f(x) = x^2 + 12x - 2x - 24
f(x) = x^2 + 10x - 24
Answer:
The value of annuity is 
Step-by-step explanation:
From the question we are told that
The periodic payment is 
The interest rate is 
Frequency at which it occurs in a year is n = 2 (semi-annually )
The number of years is 
The value of the annuity is mathematically represented as
(reference EDUCBA website)
substituting values
![P_v = 1500 * [1 - (1 + \frac{0.08}{2} )^{-22 * 2} ] * [\frac{(1 + \frac{0.08}{2} )}{ \frac{0.08}{2} } ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%201500%20%2A%20%20%5B1%20%20-%20%281%20%2B%20%5Cfrac%7B0.08%7D%7B2%7D%20%29%5E%7B-22%20%2A%202%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281%20%2B%20%5Cfrac%7B0.08%7D%7B2%7D%20%29%7D%7B%20%5Cfrac%7B0.08%7D%7B2%7D%20%7D%20%5D)
![P_v = 1500 * [1 - (1.04 )^{-44} ] * [\frac{(1.04 )}{0.04} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%201500%20%2A%20%20%5B1%20%20-%20%281.04%20%29%5E%7B-44%7D%20%5D%20%2A%20%5B%5Cfrac%7B%281.04%20%29%7D%7B0.04%7D%20%5D)
![P_v = 1500 * [1 - 0.178 ] * [\frac{(1.04 )}{0.04} ]](https://tex.z-dn.net/?f=P_v%20%20%3D%20%201500%20%2A%20%20%5B1%20%20-%200.178%20%5D%20%2A%20%5B%5Cfrac%7B%281.04%20%29%7D%7B0.04%7D%20%5D)

Do the (68+7) = 75 then do 75+93=168