Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
h = 60 ; x = 25
Step-by-step explanation:
You are going to want to use Pythagorean Theorem to solve these.
Pythagorean Theorem: a² + b² = c²
h² + 144² = 156²
h² + 20736 = 24336
h² = 3600
h = 60
x² + 60² = 65²
x² + 3600 = 4225
x² = 625
x = 25
A40=a1 +(40-1)r
in this case r is 3 beceause -2+3 will be 1 etc
a40=-2 +39*3
I don't know kid I'm busy right now
