17.429 (rounded)
17.42857142857143 (not rounded)

+ 1 = 3
First, multiply both sides by 3. / Your problem should look like: x + 3 = 9.
Second, subtract 3 from both sides. / Your problem should look like: x = 9 - 3.
Third, simplify 9 - 3 to 6. / Your problem should look like:
x = 6, which is your answer.
Answer:
Probability each player gets an ace, a $2 and a $3 = 0.0374
Step-by-step explanation:
The total number of ways to divide the card in triples among four players = 369600 ways
The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways
Probability each player gets an ace, a $2 and a $3 = 13824/369600
Probability each player gets an ace a $2 and a $3 = 0.0374
Note: Further explanation is provided in the attachment.
N = first integer
n + 1 = second integer
n + 2 = third
n + 3 = fourth
the sum is 114 so:
n + (n + 1) + (n + 2) + (n + 3) = 114
solve:
4n + 6 = 114
4n = 108
n = 27
so 27 is your first.
27 + 1 is your second (remember n +1 n +2 and n +3)
so your first four integers are: 27 28 29 and 30
(I'll also help with one)
week one: x
week two: x + 5
week three: 2(x+5) or 2x + 10
week1 + 2 + 3 = 431
so its:
x + (x+5) + (2x + 10)
4x + 15 = 431
4x = 416
x = 104
its then:
week one: 104 sold
week two: 109 sold (x + 5)
<span>week three: 218 (2x + 10)
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