Answer:
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Algebra Examples
Popular Problems Algebra Solve by Substitution 3x-4y=9 , -3x+2y=9
3
x
−
4
y
=
9
,
−
3
x
+
2
y
=
9
Solve for
x
in the first equation.
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x
=
3
+
4
y
3
−
3
x
+
2
y
=
9
Replace all occurrences of
x
in
−
3
x
+
2
y
=
9
with
3
+
4
y
3
.
x
=
3
+
4
y
3
−
3
(
3
+
4
y
3
)
+
2
y
=
9
Simplify
−
3
(
3
+
4
y
3
)
+
2
y
.
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x
=
3
+
4
y
3
−
9
−
2
y
=
9
Solve for
y
in the second equation.
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Move all terms not containing
y
to the right side of the equation.
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x
=
3
+
4
y
3
−
2
y
=
18
Divide each term by
−
2
and simplify.
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x
=
3
+
4
y
3
y
=
−
9
Replace all occurrences of
y
in
x
=
3
+
4
y
3
with
−
9
.
x
=
3
+
4
(
−
9
)
3
y
=
−
9
Simplify
3
+
4
(
−
9
)
3
.
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x
=
−
9
y
=
−
9
The solution to the system of equations can be represented as a point.
(
−
9
,
−
9
)
The result can be shown in multiple forms.
Point Form:
(
−
9
,
−
9
)
Equation Form:
x
=
−
9
,
y
=
−
9
image of graph
9514 1404 393
Answer:
- interest: $63
- balance: $9063
Step-by-step explanation:
After 6 months, the interest accrued is ...
I = Prt
I = $9000·0.014·(6/12) = $63
This is added to the principal to get the balance at that point in time.
$9000 +63 = $9063
__
The interest earned in the first 6 months is $63. The balance after 6 months is $9063.
_____
The compound interest formula will give you the same result for one compounding period. It tells you the balance is ...
A = P(1 +r/n)^(nt)
where n is the number of times interest is compounded in a year (2), and t is the number of years (1/2). For annual rate r = 1.4%, this is ...
A = $9000(1 +0.007)^(2×1/2) = $9000·1.007 = $9063
Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
<span>(3,5),
(5,8),
(6,13)
------
(14,26)/3
then use the point slope form of a line to find equation of line
</span>

<span>
Find y-intercept for x = 0.
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