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Vedmedyk [2.9K]
3 years ago
13

The Jacksons went on a 700 mile trip. On the first day they drove 6 and 2/3 hours and on the second day the drove 5 and 3/4 hour

s. How many hours did they drive during the first two days?
Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Total number of miles is 700.

On the first day, they drove 6 and 2/3 hours. We would convert 6 and 2/3 hours to improper fraction. It becomes 20/3 hours. On the second day, they drove 5 and 3/4 hours. Converting to improper fraction, it becomes 23/4 hours. Total number of hours that they drove during the first two days is the sum of hours driven on the first day and hours driven on the Second day. It becomes

20/3 + 23/4 = (80 + 69)/12

= 149/12 hours

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Flauer [41]
The answer is 0.0016 or 0.0017
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3 years ago
A circle with radius 142.5 has an arc with a 24 degree angle. What is the length of the arc?
MissTica

Answer:  59.690260418206

The result is approximate. Round that value however you need to.

===========================================================

Explanation:

For a circle with radius r = 142.5, the full distance around the edge (aka perimeter aka circumference) is found by using the formula below.

C = 2*pi*r

C = 2*pi*142.5

C = 895.353906273091

That value is approximate. I used my calculator's stored value of pi to get the most accuracy possible.

That value of roughly 895 represents the distance around a full circle of that radius, but we only want a 24 degree pizza slice.

In other words, we want 24/360 = 1/15 of the full perimeter

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5 0
2 years ago
Read 2 more answers
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
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