<span>200/40=5 5/2=2.5 2.5+5=7.5 30/7.5 = 4 hours</span>
Answer: what ever is -10 1/2
Step-by-step explanation:
Because its the lowest negative there and yea!
Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.
Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.
let
be the probability that commercial cars have rear license plates and
be the probability that connected trucks have rear license plates.
Cars Trucks Total
Total 2049 334 2383
x 239 45 284
p 0.1166 0.1347 0.1191
α=0.05
Hypothesis will be :
![H_{0}:p_{1} =p_{2}](https://tex.z-dn.net/?f=H_%7B0%7D%3Ap_%7B1%7D%20%3Dp_%7B2%7D)
![H_{1} :p_{1} < p_{2}](https://tex.z-dn.net/?f=H_%7B1%7D%20%3Ap_%7B1%7D%20%3C%20p_%7B2%7D)
It is a left tailed test at 0.05 significance.
Standard errors of p=![\sqrt{p(1-p)/n}](https://tex.z-dn.net/?f=%5Csqrt%7Bp%281-p%29%2Fn%7D)
=![\sqrt{(0.1191*0.8809)/2383}](https://tex.z-dn.net/?f=%5Csqrt%7B%280.1191%2A0.8809%29%2F2383%7D)
=
=0.0066
Test statistic Z=p difference/standard error
=(0.1166-0.1347)/0.0066
=-0.0181/0.0061
=-2.967
p value=0.001505<5%
Since p is less than 5% we reject null hypothesis.
We cannot calculate standard deviation so we cannot calculate confidence interval.
Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.
Learn more about z test at brainly.com/question/14453510
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B
I know this right away because notice how it says “EACH month.” When it includes each you have to have an “x” beside the number to make it each month. If you don’t have an x it will just be “a single month.”
Sorry if that’s confusing I’m bad at explaining but have a nice day:))