2 years ago

I need help on this question below

Mathematics

1 answer:

kumpel [21]2 years ago

3 0

I think it’s the Second one

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A concert is being held in a gymnasium that can hold no more than 550 people. A permanent bleacher will seat 30 people.. The eve

tatyana61 [14]

26
550-30=520
520/20=26

8 0

2 years ago

Explain how you would graph the line y = 2/3x + 3 using its slope and y-intercept.

Ivahew [28]

Answer:

Slope = 2/3 Y intercept +3

Step-by-step explanation:

Plot the y-intercept (0,+3) in the xy axis. Remember, this point always lies on the vertical axis y.

Starting from the y-intercept, find another point using the slope. Slope contains the direction how you go from one point to another.

The numerator tells you how much steps to go up or down (rise) while the denominator tells you how many units to move left or right (run).

Connect the two points generated by the y-intercept and the slope using a straight edge (ruler) to reveal the graph of the line.

5 0

3 years ago

Read 2 more answers

The graph below shows the length of Jutta's hair over a 6 month period. Each point represents a measurement at the beginning of

cestrela7 [59]

Her hair grew 3.6 inches between the beginning of March and the beginning of June

4 0

3 years ago

Quadrilateral CAMP below is a rhombus. The length of PQ is (x + 2) units, and the length of QA is

Phoenix [80]

Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.

<u>Step-by-step explanation:</u>

As given by the statement in the problem,

Q may be the middle point, which cut the diagonal PA into 2 equal halves.

In rhombus, diagonals meet at right angles.

which means that PQ = QA

x+2 = 3x - 14

Grouping the terms, we will get,

3x -x = 14+ 2

2x = 16

dividing by 2 on both sides, we will get,

x = 16/2 = 8

8+2 = 3(8) - 14 = 10 = PQ or QA

3 0

3 years ago

3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d

Alexxx [7]

Expand the right side:

$(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)$

$=ab^2x^3-b^2cx^2-ad^2x+cd^2$

Notice that 98 = 2 * 7 * 7, so we have $c=2$ and $d=7$ .

Then

$-ad^2=-147\implies a=\dfrac{147}{49}=3$

and

$ab^2=3\implies b^2=1\implies b=1$

6 0

3 years ago