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otez555 [7]
3 years ago
8

Write an inequality for the graph below:

Mathematics
1 answer:
Over [174]3 years ago
8 0
Y=1x+-3 i think thats what it is
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Shawn earns $10 per hour for the first 32 hours he works in a week. For any additional
olchik [2.2K]

Answer:

im sorry im not sure but i think 9

Step-by-step explanation:

5 0
3 years ago
Plzz helpp mee in this question!!!​
VashaNatasha [74]

Answer:

Please see attached picture for full solution.

4 0
3 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
I need help! Please help me and tell me how you got the answer. Will mark brainlist!
Serggg [28]

Answer:

3. <em>V= 192</em>

4. <em>V= 32</em>

Step-by-step explanation:

first, <u>find</u> the area of the base by multiplying length by width.

Once you <u>determine</u> the area of the base, multiply that by height

6 0
3 years ago
Read 2 more answers
A rectangle measures 2 4/ 5 inches by 1 1/ 5 inches. What is its area?
AlexFokin [52]

[ Answer ]

\boxed{3\frac{9}{25} }

[ Explanation ]

Area Of Rectangle: Length * Width

2 4/5 * 1 1/5

=======================

Convert Fractions Into Mixed Numbers:

2 4/5 = 14/5

1 1/5 = 6/5

Multiply Across:

14 * 6

5 * 5

= 84/ 25

Simplify:

3 9/25

\boxed{[ \ Eclipsed \ ]}

4 0
3 years ago
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