Question

At higher altitudes, water boils at lower temperatures. This relationship between altitude and boiling point is linear. At an altitude of 1000 feet, water boils at 210°F. At an altitude of 3000 feet, water boils at 206°F. Use an equation in point-slope form to find the boiling point of water at an altitude of 8000 feet. Solve the problem using an equation in point-slope form.

Answer 1

Answer:

the boiling point of water at an altitude of 8000 feet is 196°F

Step-by-step explanation:

Answer 2

Let's assume

boiling point is y

altitude is x

we are given

This relationship between altitude and boiling point is linear

At an altitude of 1000 feet, water boils at 210°F

so, first point is (1000,210)

so, x1=1000 , y1=210

At an altitude of 3000 feet, water boils at 206°F

so, second point is (3000,206)

so, x2=3000,y2=206

now, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{206-210}{3000-1000}$

$m=-\frac{1}{500}$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

so, we can plug it

$y-210=-\frac{1}{500}(x-1000)$

so, point slope form of line is

$y-210=-\frac{1}{500}(x-1000)$

now, we can plug x=8000

and then we can solve for y

$y-210=-\frac{1}{500}(8000-1000)$

$y=196$

So,

the boiling point of water at an altitude of 8000 feet is 196°F..........Answer