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dexar [7]
3 years ago
10

We have a biased coin (probability of heads is equal to 1/4). Consider the following 2 step process: In the first step we flip t

he coin until we get a heads. Let X denote the trial on which the first heads occurs. In the second step we flip the coin X more times. Let Y be the number of heads in the second step. (a) For each non-negative integer, k, what is the probability that X = k? (b) Conditioned on the event {X = k}. What is the probability Y = 0? (c) Use the Law of Total Probability to compute the unconditional probability that Y = 0.

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

See the attached pictures for answer.

Step-by-step explanation:

See the attached picture for detailed explanation.

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Just answer no need to explain.
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So, shifting x³ , 3 units to left will result in:

f(x) = (x + 3)³

Shifting down means subtracting the number from the function value. 

So, shifting 2 units down will result in:

f(x) = (x + 3)³ - 2

Therefore, option A is the correct graph
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The least common denominator of three fraction is 100. one of the fractions are 7/10. what are the other fractions.
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2 years ago
Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
faust18 [17]

Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29

b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59

c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88

d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12

e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24

f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59

3 0
3 years ago
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Rus_ich [418]

Answer:

3.47

Step-by-step explanation:

since the third decimal is less than 5 then it doesn't carry over to the 7 thus it remains 7.

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