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vekshin1
3 years ago
5

Make an equation to represent the area of a square whose sides are given by the expression x+y

Mathematics
2 answers:
yarga [219]3 years ago
7 0

Answer:

B

Step-by-step explanation:

area of a square = s² ( s is the side length )

here s = x + y, hence

area = (x + y)² ← expand using FOIL )

        = x² + xy + xy + y² = x² + 2xy + y² → B













Anastasy [175]3 years ago
4 0

Answer:

B. area = x^2 + 2xy + y^2

Step-by-step explanation:

Area of square with side s is s^2.

This square has side x + y, so

area = (x + y)^2

area = (x + y)(x + y)

area = x^2 + xy + xy + y^2

area = x^2 + 2xy + y^2

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Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the
mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ ,  μ₀ + σ]   contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ ,  μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ ,  μ₀ + 0,5σ]   ⇒  [ 78 - (0,5)*8 , 78 + (0,5)*8 ]  ⇒[ 74 , 82]

[ μ₀ - σ ,  μ₀ + σ]  ⇒ [ 78 - 8 , 78 +8 ]   ⇒  [ 70 , 86 ]

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]  ⇒ [ 78 - 12 , 78 + 12 ]  ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ ,  μ₀ + 1,5 σ]    ⇒  [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7  = 0,3 %

Only 0,3 % of population is out of   μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0
3 years ago
Solve the equation for u.<br> Uw + uq=r
soldi70 [24.7K]

Answer:  u= \frac{r}{w+q}

Step-by-step explanation:

uw + uq = r To solve for u  factor  the left side to eliminate the other variables.

u ( w + q) = r   Now divide both sides by w+q

u = \frac{r}{w+q}

4 0
3 years ago
Read 2 more answers
I need help with this because ima fail
Studentka2010 [4]

Answer:-αx-20=-14 --> \frac{-6}{x}

4=\frac{6}{a}×+5 --> a=-6

7+2ax=13---> a=\frac{3}{x}

Step-by-step explanation:

5 0
2 years ago
Find the value of x. Give reasons to justify your solution. C ∈ AE
saw5 [17]

Answer:

x = 11º

Step-by-step explanation:

1. Notice Parallel Lines

2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)

3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º

4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.

5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).

  • 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
  • 3x = 33 (inverse operations; divide by 3)
  • x = 11º (remember to apply units)
7 0
3 years ago
The box plot represents the distribution of the number of points scored by a cross country team at 12 meets. If possible, find t
Reil [10]

The median is the value equivalent to the vertical line as shown. Hence the median point is 34

<h3>What is a median?</h3>

The median is defined as the value at the middle after rearrangement.

From the given boxplot, we have the following

The minimum value is equivalent to the lower position of the whisker = 22

The maximum value is equivalent to the upper position of the whisker = 42

The median is the value vertical line in between the box = 34

The lower quartile (Q1) = starting point of the box = 33

Upper quartile (Q3) = end point of the box = 38

For the boxplot, the median is the value equivalent to the vertical line as shown. Hence the median point is 34

Learn more on boxplot here: brainly.com/question/12992903?referrer=searchResults

5 0
2 years ago
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