Question

What is the area of a circle with the equation (x - 3)^2 + (y + 2)^2 = 64

Answer 1

Answer:

200.96 square units

Step-by-step explanation:

$(x - 3)^2 + (y + 2)^2 = 64\\(x - 3)^2 + (y + 2)^2 = 8^{2} \\equating \:it\: with\\(x - h)^2 + (y -k)^2 = r^{2}\\we\:find;\\r^{2} =8^{2}\\\therefore radius\: (r) = 8 units\\Area\: of\: circle\\=\pi r^{2} \\=3.14\times8^2\\=3.14\times 64\\=200.96 \:units^{2}$