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natta225 [31]
3 years ago
6

Try, check, and revise or write an equation to solve:

Mathematics
1 answer:
olchik [2.2K]3 years ago
6 0

Answer:

42 and 7.

Step-by-step explanation:

Let the two numbers be x and y respectively.

Translating the word problem into an algebraic expression, we have;

x * y = 294

x/y = 6

x = 6y

Substituting eqn 3 into eqn 2, we have;

6y * y = 294

6y² = 294

Dividing both sides by 6, we have;

y² = 49

Taking the square root of both sides, we have;

y = 7

To find the value of x;

x = 6y

x = 6*7

x = 42

Therefore, the two whole numbers are 42 and 7.

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Answer:

The right answer is "5.9". A further solving is provided below.

Step-by-step explanation:

The given values are:

Initial Magnitude,

M₁ = 3.9

Let Second magnitude be M₂.

Now,

⇒  M_2-M_1=log(\frac{l_2}{l_1} )

On substituting the values, we get

⇒  M_2-3.9 = log (120)

On putting the value of "log 120", we get

⇒  M_2-3.9=2.079

On adding "3.9" both sides, we get

⇒  M_2-3.9+3.9=2.079+3.9

⇒                    M_2=5.9

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