Try, check, and revise or write an equation to solve:
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f(x) =
- 2
y =
- 2
This is the original equation, and now we have to find the inverse.
When finding the inverse, just flip the variables, x as y and y as x
f ⁻¹(x)
↓
x =
- 2
We have to isolate y as it is our f ⁻¹(x)
Take 2 to the other side { When you see subtraction, you do addition }
x + 2 =
Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y
f ⁻¹ (x) = 9x + 18
f(x) =
y =
This is the original equation, and now we have to find the inverse.
When finding the inverse, just flip the variables, x as y and y as x
f ⁻¹(x)
↓
x =
We have to isolate y as it is our f ⁻¹(x)
Take 2 to the other side { When you see subtraction, you do addition }
x + 2 =
Take 9 to the other side { When you see division, you do multiplication }
9 ( x + 2 ) = y
9x + 18 = y
f ⁻¹ (x) = 9x + 18
Answer:
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
Step-by-step explanation:
Bayes Theorem:
Two events, A and B.
In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.
In this question:
Event A: Forecast of rain.
Event B: Raining.
In recent years, it has rained only 5 days each year.
A year has 365 days. So
When it actually rains, the weatherman correctly forecasts rain 90% of the time.
This means that
Probability of forecast of rain:
90% of 0.0137(forecast and rains)
10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)
What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain
11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain