Answer:
see below
Step-by-step explanation:
Using the segment addition postulate
AB + BC = AC
x+2 + 7x-3 = AC
Combine like terms
8x -1 = AC
Using the segment addition postulate
PQ + QR = PR
8y+5 + QR = 13y+25
Subtract 8y from each side
5 + QR = 13y-8y+25
5 + QR = 5y+25
Subtract 5 from each side
QR = 5y+25-5
QR = 5y+20
If you are talking about finding the slope of BC then it looks like you have to find the square root of 3 which is approx 1.7 then find the slope.
slope equation is rise over run (or y over x): y1 + y2 divided by x1 + x2.
From this you should be able to find the answer
Answer: x-intercept = (3,0); y-intercept = (0,7)
Step-by-step explanation:
-3y = 7x - 21
y = -7/3 x + 7 (divide both sides by -3)
y-intercept = (0,7) (y = mx + b; b is always y-intercept)
0= -7/3 x + 7 (plug in 0 for y to get x-intercept)
-7/3x = -7 (subtract 7 from both sides)
x = 3 (divide both sides by -7/3)
x-intercept = (3,0)
F – 12 = –35
Here, we must solve for f
f - 12 = -35
+12 +12
f = -35 + 12
f = -23
Answer: f = -23
Answer:
(7x-1)(x-3)
Step-by-step explanation:
7x^2 - 22x + 3
The factors have to add to -22, but multiply to equal 3. But since the "a" value has a number on it, you have to use it too.
(7x +/- [n1]) ( x +/- [n2]) = 7x^2 - 22x + 3
Since the two numbers multiply to a positive value, they have to have the same sign. (7x-1) (x-3) works to produce the expression when it's foiled.
