Two planes left the same airport traveling in opposite directions. The first plane left at 9:00 a.m. and 2.25 h later, the two p
lanes were 1825 mi apart. The second plane left at 10:00 a.m. and its average rate was 108 mph slower than the first plane's average rate. What was the first plane's average rate? Let x represent the first plane's average rate.
Enter an equation that can be used to solve this problem in the first box. Solve for x and enter the first plane's average rate in the second box.
Formula for calculating the distance : d = v * t, where v is the velocity and t is the time. We have two planes that are traveling in the opposite directions. d = 2.25 x + 1.25 * ( x - 108 ) 1,825 = 2.25 x + 1.25 x - 135 1,825 + 135 = 3.5 x x = 1,960 : 3.5 x = 560 Answer: Equation : 1,825 = 2.25 x + 125 *( x - 135 ) x = 560 mph
.5 * .5 *.5 = 1/8 - - the probability to have head is .5 so the probability of tails 1-.5 - then the first time is head the second time is head the third time is tail so .5 * .5 *.5 = 1/8
