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ioda
3 years ago
15

Please help if possible thank you

Mathematics
1 answer:
Helga [31]3 years ago
5 0

y =  \frac{3}{2}
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Determine which ordered pair is a solution of y=8X
Amanda [17]
<span>A.(0,8) B.(-1,8) C.(1.5,10) D.(2,16)

Simply substitute the value of x to get the value of y.

y = 8x

(0,8) y = 8(0) ; y = 0

(-1,8) y = 8(-1) ; y = -8

(1.5,10) y = 8(1.5) ; y = 12

(2,16) y = 8(2) ; y = 16 

The correct ordered pair is D. (2,16)</span>
5 0
2 years ago
Brainliest for whoever gets this right!
My name is Ann [436]

Answer:

x=\frac{(a^2+ab)}{a-b}

Step-by-step explanation:

So we want to make x the subject of the formula:

a(x-b)=a^2+bx

First, distribute the left side:

a(x)-a(b)=a^2+bx\\ax-ab=a^2+bx

Combine all the terms with x with it on one side. To do this, first subtract bx from both sides. The right side cancels:

(ax-ab)-bx=(a^2+bx)-bx\\ax-ab-bx=a^2

Remove the -ab from the left. Add ab to both sides. The left side cancels:

(ax-ab-bx)+ab=a^2+ab\\ax-bx=a^2+ab

Now, distribute out the x from the left side:

ax-bx=a^2+ab\\x(a-b)=a^2+ab

Divide both sides by (a-b). The left side cancels:

\frac{(x(a-b))}{a-b}=\frac{(a^2+ab)}{a-b}  \\x=\frac{(a^2+ab)}{a-b}

Therefore:

x=\frac{(a^2+ab)}{a-b}

5 0
3 years ago
Read 2 more answers
Avaluate 2^3x-1 for x=1
DENIUS [597]

<em><u>Answer:</u></em>

4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.

<em><u>Step-by-step explanation:</u></em>

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was 2^{3x-1} or 2^{3x}-1, so I'll be doing both:

For 2^{3x-1}, we should plug in x to get 2^{3(1)-1} and then simplify to get 2^{2}.

2 to the power of 2 or 2^{2} is equal to 2 * 2 or 4.

The second one, 2^{3x}-1, we should plug in x to get 2^{3(1)}-1 and then to become 2^{3}-1. 2 to the power of 3 or 2^{3} is 8 and then minus 1 is 7.

7 0
3 years ago
Read 2 more answers
What is 2/5 + 1/9 I need help
Fantom [35]
Find the LCD of both fractions and that is 45.

Make the denominators the same as the LCD

Simplify, now denominators are the same

join the denominators

simplify 

Answer: 23/45
5 0
3 years ago
Please solve the following sum or difference identity.
xxTIMURxx [149]

Answer:

sin(A - B) = \frac{4}{5}

Step-by-step explanation:

Given:

sin(A) = \frac{24}{25}

sin(B) = -\frac{4}{5}

Need:

sin(A - B)

First, let's look at the identities:

sum: sin(A + B) = sinAcosB + cosAsinB

difference: sin(A - B) = sinAcosB - cosAsinB

The question asks to find sin(A - B); therefore, we need to use the difference identity.

Based on the given information (value and quadrant), we can draw reference triangles to find the simplified values of A and B.

sin(A) = \frac{24}{25}

cos(A) = \frac{7}{25}

sin(B) = -\frac{4}{5}

cos(B) = \frac{3}{5}

Plug these values into the difference identity formula.

sin(A - B) = sinAcosB - cosAsinB

sin(A - B) = (\frac{24}{25})(\frac{3}{5}) - (-\frac{4}{5})(\frac{7}{25})

Multiply.

sin(A - B) = (\frac{72}{125}) + (\frac{28}{125})

Add.

sin(A - B) = \frac{4}{5}

This is your answer.

Hope this helps!

6 0
3 years ago
Read 2 more answers
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