Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Answer:
you get 6.90372 so i thnk it is clse to B
≈ 30.43 , lmk if u need an explanation
10 whole sandwiches can be made with 2 pounds of cheese if each sandwhich has 3 ounces of cheese on it.
2 pounds = 32 ounces
32/3 = 10.67
Hello,
Let's z=0.1234567891011121314151617181920.....(never end)
2/5=(2/(5z)*z<3241/1000 *z
3/4=(3/(4z))*z>6075/1000*z
So here is 2836 irrational numbers:
3241*z/1000
3242*z/1000
3243*z/1000
...
6073*z/1000
6074*z/1000
6075*z/1000
