How do you write 9,800,100 in exponents and expanded form

Select all polynomials that have (x-3)(x−3)left parenthesis, x, minus, 3, right parenthesis as a factor. Choose all answers that

iVinArrow [24]

Answer:

A, C, D

Step-by-step explanation:

One way to answer this question is to use synthetic division to find the remainder from division of the polynomial by (x-3). If the polynomial is written in Horner form, evaluating the polynomial for x=3 is substantially similar.

A(x) = ((x -2)x -4)x +3

A(3) = ((3 -2)3 -4)3 +3 = -3 +3 = 0 . . . . . has a factor of (x -3)

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B(x) = ((x +3)x -2)x -6

B(3) = ((3 +3)3 -2)3 -6 = (16)3 -6 = 42 . . . (x -3) is not a factor

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C(x) = (x -2)x^3 -27

C(3) = (3 -2)3^3 -27 = 0 . . . . . . . . . . . . . has a factor of (x -3)

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D(x) = (x^3 -20)x -21

D(3) = (3^3 -20)3 -21 = (7)3 -21 = 0 . . . . has a factor of (x -3)

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The polynomials of choice are A(x), C(x), and D(x).

4 0

3 years ago

It takes Evan 6 3/4 hours to mow 3 lawns. it takes him 2 1/3 hours to mow Mr. Smiths yard and 1 3/4 hours to mow Ms. Lee's yard.

Ratling [72]

Answer: $2\frac{2}{3}\ hours$

Step-by-step explanation:

Given: The total time taken by Evan to mow the 3 lawns = $6\frac{3}{4}=\frac{27}{4}\ \text{hours}$

Time taken by Evan to mow the first lawn = $2\frac{1}{3}=\frac{7}{3}\ \text{hours}$

Time taken by Evan to mow the second lawn = $1\frac{3}{4}=\frac{7}{4}\ \text{hours}$

Now,Time taken by Evan to mow the third lawn = $\frac{27}{4}-\frac{7}{3}-\frac{7}{4}$

⇒Time taken by Evan to mow the third lawn = $\frac{81-28-21}{12}$

⇒Time taken by Evan to mow the third lawn = $\frac{32}{12}=\frac{8}{3}=2\frac{2}{3}\ hours$

Hence, the time taken by Evan to mow the third lawn = $2\frac{2}{3}\ hours$

7 0

3 years ago

A group of young businesswomen wish to open a high fashion boutique in a vacant store, but only if the average income of househo

vova2212 [387]

Answer:

Based on the results the boutique could be located there.

Step-by-step explanation:

Note: The average income (the mean) is calculated by summing the total incomes then divided by the total sample–9.

The mean ù (average income) = $28,000 + $24,000 + $26,000 + $25,000 + $23,000 + $27,000 + $26,000 + $22,000 + $24,000= $225,000/9= $25,000 (which is ≥ $25,000.

Based on the results of the p-value, using the 5% significant level we fail to reject the null hypothesis (ú≥25,000).

7 0

3 years ago

(please help me)The center of a circle is at (8, —8). One point on the circle is at (8, —3). What is the area of the circle? (Us

Serjik [45]

Answer:

it A or C depending on the site you use

Step-by-step explanation:

good luck

7 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap

11Alexandr11 [23.1K]

Answer:

0.25 feet per minute

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

$\dfrac{dV}{dt}=20$ ft^3/min$

$\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h$

Since base diameter = Height of the Cone

Radius of the Cone = h/2

Therefore,

$\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}$

$\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}$

Therefore: $\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=20$

We want to determine how fast is the height of the pile is increasing when the pile is 10 feet high.

$h=10$ feet$\\\\\dfrac{3\pi *10^2}{12}\dfrac{dh}{dt}=20\\25\pi \dfrac{dh}{dt}=20\\ \dfrac{dh}{dt}= \dfrac{20}{25\pi}\\ \dfrac{dh}{dt}=0.25$ feet per minute (to two decimal places.)$

When the pile is 10 feet high, the height of the pile is increasing at a rate of 0.25 feet per minute

5 0

3 years ago