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3 years ago

4/3 ×π×7×7×7. Leave your answer in pi.

Mathematics

2 answers:

Alina [70]3 years ago

6 0

Answer:

1436.8

Step-by-step explanation:

In pi it is = 1372/3 pi

RoseWind [281]3 years ago

4 0

Answer:

Step-by-step explanation:

$\frac{4}{3}*\pi *7*7*7=\frac{1372}{3}*\pi \\\\\=457.33\pi$

Multiply 4*7*7*7 = 1372

Divide 1372 by 3

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3 years ago

Evaluate the expression for n = 8.<br> 6(n + 1) =?

e-lub [12.9K]

Answer:

Step-by-step explanation:

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3 years ago

A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years

juin [17]

Answer: 0.55567

Step-by-step explanation:

Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.

i.e.

$\mu=10\text{ years}\\\sigma=3\text{ years}$

Let $X_1$ and $X_2$ are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator $X_3$ .

So that, $X =X_1+X_2-1.9\times X_3$

Mean $=E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1$

Standard deviation = $\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}$

$=\sqrt{(3^2+3^2+(1.9\times3)^2)}$

$=7.1056315694$

Z-score : $z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14$

Now , The probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

$P(Z>-0.14)=P(Z$

Hence, the required probability is 0.55567.

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3 years ago

Which statement is true about the expression 12-7+3

Amiraneli [1.4K]

The answer to the question is 8

6 0

3 years ago

Read 2 more answers

The Thomas Supply Company Inc. is a distributor of gas-powered generators. As with any business, the length of time customers ta

Dmitry [639]

Answer:

The answer is below

Step-by-step explanation:

When computing quartile and decile, the data must be arranged in ascending order.

Given the data points:

13 13 13 20 26 26 29 31 34 34 35 35 36 37 38 41 41 41 42 43 46 47 48 49 53 55 56 62 67 82

The numbers are arranged in ascending order. The total number of terms is 30.

$First \ quartile(Q_1)=\frac{1}{4}(n+1)^{th}\ term\\\\where\ n=number\ of\ terms. Hence:\\\\Q_1=\frac{1}{4}(30+1)=7.75^{th}\ term=average\ of\ 7th\ and\ 8th\ term=\frac{29+31}{2} =30\\\\Q_1=30\\\\Third \ quartile(Q_3)=\frac{3}{4}(n+1)^{th}\ term\\\\Q_3=\frac{3}{4}(30+1)=23.25^{th}\ term=average\ of\ 23rd\ and\ 24th\ term=\frac{48+49}{2} =48.5\\\\Q_3=48.5$

$Second \ decile(D_2)=\frac{2}{10}(n+1)^{th}\ term\\\\where\ n=number\ of\ terms. Hence:\\\\D_2=\frac{2}{10}(30+1)=6.2^{th}\ term=average\ of\ 6th\ and\ 7th\ term=\frac{26+29}{2} =27.5\\\\D_2=27.5\\\\\\Eight \ decile(D_8)=\frac{8}{10}(n+1)^{th}\ term=\frac{8}{10}(30+1)=24.8^{th}\ term\\=average\ of\ 24th\ and\ 25th\ term=\frac{49+53}{2} =51\\\\D_8=51$

6 0

3 years ago

4/3 ×π×7×7×7. Leave your answer in pi.​

4/3 ×π×7×7×7. Leave your answer in pi.