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3 years ago

Identify the slope, x-intercept, and y-intercept. I 1.y=x+5 2. y = - 4x 3. -2x + 3y = 12

1 answer:

4 0

1.) slope is 1 and y intercept is 5 x intercept is -5
2.) slope is -4 and y intercept is 0 x intercept is 0
3.) slope is 2/3 and y intercept is 4 x intercept is -6

Hope this helps

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A+B share a ratio of 2:3 A pays 126 how much does B pay

Alenkasestr [34]

A:B = 2:3

A=126
B=?

126/2=63

63x3=189

A=126
B=189

A:B = 126:189

6 0

3 years ago

Please help

Alenkasestr [34]

Answer:

Domain: {-4, -2, 1, 2, 4}

Range: {-4, -2, -1, 1, 4}

The relation is a function.

Step-by-step explanation:

A relation is any set of ordered pairs, which can be thought of as (input, output).

A function is a relation in which no two ordered pairs have the same first component and different second components.

Remember that a function can only take on one output for each input. We cannot plug in a value and get out two values.

The Vertical Line Test allows us to know whether or not a graph is actually a function. If a vertical line intersects the graph in all places at exactly one point, then the relation is a function.

I did the Vertical Line Test on your given graph. As you can see from the attached screenshot, each vertical line crosses the graph only once. Therefore, the given relation is a function.

The domain of the given relation is the set of x-values, while the range is the set of y-values. You'll have to list the ordered pairs in order to determine the domain and range of the given relation.

Relation: {(-4, -1), (-2, 1), (1, -2), (2, 4), (4, -4)}.

Domain: {-4, -2, 1, 2, 4}

Range: {-4, -2, -1, 1, 4}

Please mark my answers as the Brainliest if you find my explanations helpful :)

4 0

3 years ago

Great day if anyone wants to help!

Aloiza [94]

Answer:

1. Vertex: (4,26)

X-intercept: (9.09,0)(-1.09)

2. Vertex: (-4,-6)

X-intercept: (-1.55,0)(-6.44,0)

Step-by-step explanation:

7 0

2 years ago

Which of the following numbers are irrational? A.9/15 B.18 squared C.9 squared D.169 squared E. 78 squared

finlep [7]

Answer is A.9/15
'''''''''''''''''''''''

An irrational number cannot be expressed as a ratio between two numbers and it cannot be written as a simple fraction because there is not a finite number of numbers when written as a decimal.

6 0

3 years ago

Find the exact value of sin(cos^-1(4/5))

boyakko [2]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2762144

_______________

Let $\mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}$

$\mathsf{0\le \theta\le\pi,}$ because that is the range of the inverse cosine funcition.

Also,

$\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}$

Square both sides and apply the fundamental trigonometric identity:

$\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}$

$\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}
$

$\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}$

But $\mathsf{0\le \theta\le\pi,}$ which means $\theta$ lies either in the 1st or the 2nd quadrant. So $\mathsf{sin\,\theta}$ is a positive number:

$\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: inverse trigonometric function cosine sine cos sin trig trigonometry

3 0

3 years ago

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