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4 years ago

Please help.. i think the first and fourth are the correct answers but im not 100% sure

Mathematics

2 answers:

Dimas [21]4 years ago

8 0

This one is correct good job,anymore questions

iris [78.8K]4 years ago

6 0

1) NO = NM
3) ON = ½SU
5) ST = 2ON

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A standardized test that colleges use to make admissions decisions is the _____.

Aloiza [94]

Answer:

Step-by-step explanation:

EXPLORE test is the college test ACT's "prep" version mostly for 8th and 9th graders.

ASVAB (Armed Services Vocational Aptitude Battery) test is used for military entrance exam.

PLAN is also like EXPLORE that it is a "prep" test for ACT but usually given to sophomore (10th grade) students. This has been discontinued from 2014, though.

SAT is a standardized test administered by College Board and is a widely used common Undergraduate University admissions exam. Colleges use this to make admissions decisions.

Thus, D is the correct choice.

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3 years ago

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Solve the system by the elimination method.

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10x + 2y - 6 = 0

Multiply 5x + y - 3 = 0 by 2

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3 years ago

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What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$x(x-2)-3(x-2)=0$

Now you can rewrite the equation as $(x-3)(x-2)=0$

Now, apply the Zero Product Property and solve for x as such:

$x-3=0\\x=3\\\\x-2=0\\x=2$

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

$2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}$

Since both solutions hold true when x = 2 and x = 3, your answer is C. x = 2 or x = 3.

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The form f(x) = a(bx) equals a. The initial value of the function f(x) = a(bx) is always a. This is due to the fact that an is not reliant on x. As a result, if x changes, bx will change as well, but a will not.

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3 years ago

A recipe uses 5 cups of water for every 3 cups of flour?

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Answer:

There's no context for a conclusion.

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