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4 years ago

Round 249,982 to the nearest hundred

2 answers:

7 0

Hundred (100) means the 3rd number from the right, which is: 249,982 . So use the number before that (further to the right) to determine whether you will round up or stay the same, which is 249,982

The number before the hundreds spot (8) is greater then 5, therefore we will round the number in the hundreds spot up 1

Since the number above 9 is 10 you will have to round the number in the thousands spot up as well

249,982

And it looks like the number in the thousands spot is 9 and the next number up is 10. This means you will have to round the number in the ten thousands place up 1

249,982

so...

250,000

Hope this helped!

~Just a girl in love with Shawn Mendes

mariarad [96]4 years ago

7 0

Answer:

250000

Step-by-step explanation:

hundred thousand ten thousand thousand, hundred ten one

2 4 9 , 9 8 2

We are rounding to the nearest hundred, so we look at the tens place

8 ≥5 so we round the hundreds place up

9 will round to 10 so the thousands place gets one bigger and the hundreds place is a zero

9 will become to 10 so the ten thousands place gets one bigger at 5 and the thousands place is a zero

249,982 becomes 250,000

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Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

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Hunter-Best [27]

Answer:

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4 years ago

Round 249,982 to the nearest hundred​

Round 249,982 to the nearest hundred