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3 years ago

Round 249,982 to the nearest hundred

2 answers:

7 0

Hundred (100) means the 3rd number from the right, which is: 249,982 . So use the number before that (further to the right) to determine whether you will round up or stay the same, which is 249,982

The number before the hundreds spot (8) is greater then 5, therefore we will round the number in the hundreds spot up 1

Since the number above 9 is 10 you will have to round the number in the thousands spot up as well

249,982

And it looks like the number in the thousands spot is 9 and the next number up is 10. This means you will have to round the number in the ten thousands place up 1

249,982

so...

250,000

Hope this helped!

~Just a girl in love with Shawn Mendes

mariarad [96]3 years ago

7 0

Answer:

250000

Step-by-step explanation:

hundred thousand ten thousand thousand, hundred ten one

2 4 9 , 9 8 2

We are rounding to the nearest hundred, so we look at the tens place

8 ≥5 so we round the hundreds place up

9 will round to 10 so the thousands place gets one bigger and the hundreds place is a zero

9 will become to 10 so the ten thousands place gets one bigger at 5 and the thousands place is a zero

249,982 becomes 250,000

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3 years ago

Read 2 more answers

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Answer:

This assume the equation is 35y = mx + c, and that r is meant to be x.

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2 years ago

Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel

Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ( $x_o, y_o, z_o$ ) and are parallel to $\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}$

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

$x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct$

x = 4 + t

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Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

$\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}$ $\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}$ $\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}$