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Karo-lina-s [1.5K]
4 years ago
9

Round 249,982 to the nearest hundred​

Mathematics
2 answers:
Marrrta [24]4 years ago
7 0

Hundred (100) means the 3rd number from the right, which is: 249,982 . So use the number before that (further to the right) to determine whether you will round up or stay the same, which is 249,982

The number before the hundreds spot (8) is greater then 5, therefore we will round the number in the hundreds spot up 1

Since the number above 9 is 10 you will have to round the number in the thousands spot up as well

249,982

And it looks like the number in the thousands spot is 9 and the next number up is 10. This means you will have to round the number in the ten thousands place up 1

249,982

so...

250,000

Hope this helped!

~Just a girl in love with Shawn Mendes

mariarad [96]4 years ago
7 0

Answer:

250000

Step-by-step explanation:

hundred thousand  ten thousand  thousand, hundred  ten one

 2                                  4                     9           , 9               8   2

We are rounding to the nearest hundred, so we look at the tens place

8 ≥5 so we round the hundreds place up

9 will round to 10 so the thousands place gets one bigger and the hundreds place is a zero

9 will become to 10 so the ten thousands place gets one bigger at 5 and the thousands place is a zero

249,982 becomes 250,000

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447 / 50

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A cash box contains $74 made up of quarters, half-dollars, and one-dollar
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Step-by-step explanation:

First, set up equations based on the information given:

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q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

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Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

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Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

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Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

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