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3 years ago

Factor: −22d³+33d²+33

Mathematics

1 answer:

Studentka2010 [4]3 years ago

7 0

Answer:

-2d^3 +3d^2 +3

Step-by-step explanation:

The biggest number you can take out of each term would be 11, so you divide each term individually by 11.

-22/11= -2

33/11=3

Then you keep the variables the same because you don't have a d in every term, therefore you cannot remove a d.

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( 70 POINTS BRAINLIST) an offshore windmill is partly submerged in the ocean. it's tallest point is 120 meters above sea level i

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Answer:

half of it would be 45

Step-by-step explanation:

120 - 30 = 90

90 divided by 2 = 45

hope this helped! sorry if i didn't answer your question, i was a little bit confused on what you wanted us to solve:)

if u want to find the length of it, it would be 150 because 120 + 30 = 150

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2 years ago

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2 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint.

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Answer:

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Step-by-step explanation:

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3 years ago

Liquid A and liquid B are mixed to make liquid C.

natta225 [31]

Answer:

Density is defined as:

Density = mass/volume.

We know that:

For liquid A:

Density = 70kg/m^3

Mass = 1400kg

Then the volume is:

Volume = mass/density = (1400kg)/(70kg/m^3) = 20 m^3

For liquid B:

Density = 280 kg/m^3

Volume = 30m^3

We can find the mass of liquid B as:

mass = density*volume = (280kg/m^3)*(30m^3) = 8400 kg

We know that liquid C is a mixture of liquid A and B.

Then the mass of liquid C will be equal to the sum of the masses of liquid A and B, then:

Mass of liquid C = 1400kg + 8400kg = 9800kg

The same happens for the volume, then:

Volume of liquid C = 30m^3 + 20m^3 = 50m^3

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3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

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3 years ago