Answer:
The probability that all three batteries would fail is given as:
= 0.000125
Step-by-step explanation:
Given that the probability of the new battery failing = 1/20 or 0.05,
Therefore, the probability that all three batteries would fail is given as:
= Probability of battery A failing * Probability of battery B failing * Probability of battery C failing
= P(A)*P(B)*P(C)
= 0.05 * 0.05 * 0.05
= 0.000125
Answer:
Thx have a great day :)
Step-by-step explanation:
Answer:
n > p + 1 + 7k
Step-by-step explanation:
21k - 3n + 9 > 3p + 12
21k - 3n > 3p + 12 - 9
3n > 3p + 3
3n > 3p + 3 + 21k
n > (3p + 3 + 21k)/3
n > p + 1 + 7k
(x^1/2 y^-2/3)^-6
= x^(1/2*-6) y^[(-2/3) *(-6)]
= x^-3 y ^4
= y^4 / x^3
answer is D. y^4 / x^3
Answer:
3 and 4
Step-by-step explanation:
