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2 years ago

Help with this problem?

Mathematics

1 answer:

ankoles [38]2 years ago

5 0

3(x-8)=12
I got this equation since there are three of the "x-8" sections that add up to the twelve length bar above

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K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

2 years ago

Please help me with this

Alisiya [41]

Woahhhh lol one sec

8 0

2 years ago

I'm not sure how you spell it, but it's the abbreviation for the Socials, the jet set, the West-side rich kids. It's like the te

ale4655 [162]

Answer:

I think it is B

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

WILL GIVE BRAINLIEST, SUPERB RATING, AND THANKS!

viktelen [127]

Look at the picture.

1 unit right (+1); 2 units down (-2)

A(1, 3) → A'(1+1, 3-2) → A'(2, 1)

B(4, 5) → B'(4+1, 5-2) → B'(5, 3)

C(3, 1) → C'(3+1, 1-2) → C'(4, -1)

(x, y) → (x + 1, y - 2)

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3 years ago

You have a can that is in the shape of a cylinder. It has a volume of about 1,728 cubic centimeters. The height of the can is 22

Harlamova29_29 [7]

Answer:

v=pi.r^2.h

1728=3.14*22r^2

1728/69.08=r^2

r^2=25.0144

r=5

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2 years ago