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Sphinxa [80]
3 years ago
8

How do you find the square root of a number?

Mathematics
2 answers:
ollegr [7]3 years ago
8 0
Most likely a calculator is your best bet for odd numbers.
There are many common squares and many common square roots, such as :
1 squared =1
2 squared =4
3 squared = 9
4 squared =16
5 squared = 25
6 squared = 36 and so on...
same with square roots
root 25 is equal to 5
root 16 is equal to 4
root 9 is equal to 3
root 4 is equal to 2
and so on however not every number works out that way so a calculator is often your best bet to find the exact value
kkurt [141]3 years ago
3 0
Just multiply by itself
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Joey bought a dozen oranges for $3.50 and several bananas for $0.25 each at the grocery store. Joey spent a total of $5.75 on th
blagie [28]

Answer:

9 bananas

Step-by-step explanation:

7 0
2 years ago
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Find the missing side (X) round to the nearest hundredth
nata0808 [166]

Answer:

\displaystyle 18,28 ≈ x

Step-by-step explanation:

\displaystyle \frac{x}{11} = csc\:37 \hookrightarrow 11csc\:37 = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

<em>OR</em>

\displaystyle \frac{11}{x} = sin\:37 \hookrightarrow xsin\:37 = 11 \hookrightarrow \frac{11}{sin\:37} = x \hookrightarrow 18,278041552... = x \\ \\ 18,28 \approx x

Information on trigonometric ratios

\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ

I am joyous to assist you at any time.

7 0
2 years ago
This is a question from my sibling's math class.
Solnce55 [7]

Answer:

14

Step-by-step explanation:

You can solve using PEMDAS:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

3(2+5)-5(3)+8=?

3(7)-5(3)+8=?

No exponents

3(7)-5(3)+8=?

21-15+8=?

No division

21-15+8=?

21-7=?

21-7=14

3(2+5)-5(3)+8=14

5 0
2 years ago
Read 2 more answers
The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 intersect to form the sides of a right triangle. Find the perimeter and area
tino4ka555 [31]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Determining the perimeter and area of the triangle giving line equation</h3>

In order to determine the area and perimeter of the lines, we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

The points of intersection of the line are;

(x₁, y₁) = (- 0.4, 5.2),

(x₂, y₂) = (-0.8, 4.4),

(x₃, y₃) = (0, 4)

Determine the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

Determine the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

<u>For the area</u>

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/12010318

#SPJ1

3 0
1 year ago
1
aleksley [76]
Answer: 3.71 miles (approximately)

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