Answer:
x = 21
Step-by-step explanation:
If RECT is a rectangle, each of its interior angles are right angles, 90°. Since ∠RTC is split into two angles, the sum of the two angles must be 90°. (Angles that add to 90° are called complementary angles).
∠RTC = ∠RTE + ∠ETC Formula for complementary angles
90 = 2x + 6 + 42 Substitute the angles
90 = 2x + 48 Combined like terms to simplify
Now isolate "x" to solve
90 - 48 = 2x + 48 - 48 Subtract 48 from both sides
42 = 2x
42/2 = 2x/2 Divide both sides by 2
x = 21
Therefore x is 21.
Answer: 8 feet
Step-by-step explanation:
Draw a right triangle and label the sides using the given information. (Drawing below) Use pythagorean theorem to find the missing length:
a^2 + b^2 = c^2
(building)^2 + (missing piece)^2 = (ladder)^2
6^2 + x^2 = 10^2
36 + x^2 = 100. subtract 36
x^2 = 64. square root of both sides
x = 8
Answer:
3rd option
Step-by-step explanation:
(
)(x)
= 
=
← factorise numerator and denominator
=
← cancel (2x + 1) on numerator/ denominator
= 
Answer:
Anything greater than or equal to 17.
Step-by-step explanation:
7/8 of 17 is 14.875
Answer:
3. 43.96 cm
4. 81.64 ft
Step-by-step explanation:
3. The formula for the circumference of a circle in terms of radius is ...
C = 2πr
When π is approximated by 3.14, this becomes ...
C ≈ 6.28r
The only answer choice even close to 6.28×(7 cm) is the one shown above.
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4. The formula for the circumference of a circle in terms of diameter is ...
C = πd
When π is approximated by 3.14, this becomes ...
C ≈ 3.14d
The only answer choice anywhere close to 3.14×(26 ft) is the one shown above.
_____
<em>Comment on the solution</em>
For questions like these, you only need to be able to estimate the answer to 1 or 2 significant digits. The answer choices are not so close together as to cause any confusion.
6×7 = 42, so the answer will be a few more than 42.
3×26 = 78, so the answer will be within a few numbers larger than that.
In each case, the answer is the largest value on the list. The other choices differ by a factor of 2, so aren't even close.