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storchak [24]
2 years ago
6

Write the first six terms of the sequence f(n)=n^3+2​

Mathematics
1 answer:
andrey2020 [161]2 years ago
4 0

Answer:

3,10,29,66,127,218

Step-by-step explanation:

f(n) = n^3 +2\\\\f(1) = 1^3 +2 = 1+2=3\\\\f(2)  =2^3 +2 = 8+2=10\\\\f(3)=3^3 +2 = 27+2 = 29\\\\f(4)  = 4^3 +2 = 64 +2 = 66\\\\f(5) = 5^3 +2 = 125+2 = 127\\\\f(6) = 6^3 +2 = 216+2 = 218

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Bhargav buys five roast beef and three  vegetarian sandwiches and the order costs $27.50. This can be represented by the equation:

5x + 3y = 27.50     (1)

Bhargav buys 2 roast beef and 6  vegetarian sandwiches and the order costs $23.00. This can be represented by the equation:

2x + 6y = 23.00     (2)

To find x and y, we have to solve equation 1 and 2 simultaneously. Multiply equation 1 by 2 and subtract equation 2 from the result:

8x = 32

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Find out more at: brainly.com/question/16763389

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An equation of a line through (-1,4) which is perpendicular to the line y = 4x + 1 and the slope is -1/4 what is the y-intercept
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The equation of the line is y=-\frac{1}{4}x+\frac{15}{4}

The y - intercept of the equation is \frac{15}{4}

Explanation:

Given that the equation of the line is y=4 x+1 and the slope is m=-\frac{1}{4}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-1,4) and the slope m=-\frac{1}{4} , we get,

y-4=-\frac{1}{4}(x+1)

Simplifying, we get,

y-4=-\frac{1}{4}x-\frac{1}{4}

     y=-\frac{1}{4}x-\frac{1}{4}+4

     y=-\frac{1}{4}x+\frac{15}{4}

Thus, the equation of the line is y=-\frac{1}{4}x+\frac{15}{4}

<u>y - intercept:</u>

The y - intercept of the equation is value of y when x = 0

Hence, substituting x = 0 in the equation y=-\frac{1}{4}x+\frac{15}{4}, we get,

y=-\frac{1}{4}(0)+\frac{15}{4}

y=\frac{15}{4}

Thus, the y - intercept of the equation is \frac{15}{4}

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