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Arada [10]
3 years ago
7

In the expression z-2t+49-q, what is 49 called?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0
I think
it’s a uhhhh , i think it’s a carrot
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.08 is 10 times as much as
Mazyrski [523]
It is 10 times as much as .008

Do you see the pattern?
5 0
3 years ago
Femi drove 290 miles from his college to home and used 23.2 gallons of gasoline. His sister, Kehinde, drove 225 miles from her c
Nata [24]

to find miles per gallon we simply do D/G

D = distance

G = gallons

290/23.2 = 12.5 mpg

225/15 = 15 mpg

Kehinde has better gas mileage.

3 0
3 years ago
Read 2 more answers
Simplify to create an equivalent expression of<br> 2(−n−3)−7(5+2n)
musickatia [10]
<h3>Answer:   -16n-41</h3>

Work Shown:

2(-n-3) -7(5+2n)

2(-n)+2(-3) - 7(5)-7(2n) ... distribute

-2n - 6 - 35 - 14n

(-2n-14n) + (-6-35)

-16n - 41

6 0
3 years ago
Please help with 13 14 15 16
Vikentia [17]

The domain and the range for the relations are given as follows:

  • 13. Domain x ∈ R, range y ∈ R.
  • 14. Domain {x ∈ Z| -4 ≤ x ≤ 4 and x is even} , range y ∈ {y ∈ Z| -1 ≤ y ≤ 4}.
  • 15. Domain {x ∈ Z| -4 ≤ x ≤ 1} , range y ∈ {y ∈ Z| -4 ≤ y ≤ 1}.
  • 16. Domain x ∈ R, range y ∈ R.

<h3>What are the domain and range of a function?</h3>

  • The domain of a function is the set that contains all possible input values. Hence, in a graph, the domain is given by the values of x.
  • The range of a function is the set that contains all possible output values. Hence, in a graph, the domain is given by the values of y.

For items 13 and 16, the functions are continuous, hence it is over the real numbers, and both the domain and range are all real values.

For items 14 and 15, the functions are discrete, hence it is over the integer numbers, and the domain is composed by the values assumed by x and the range is composed by the values assumed by y.

More can be learned about domain and range at brainly.com/question/10197594

#SPJ1

5 0
1 year ago
Derive cos (2x - 1)​
ExtremeBDS [4]

Answer:

Step-by-step explanation:

I believe that what you want to do here is to "differentiate" cos (2x - 1).

We must use the rule for differentiating cos x and also the chain rule, since the input to cos x here is (2x - 1).

(d/dx) is the derivative operator.

(d/dx) (cos x) = -sin x

(d/dx) cos (2x - 1) = - sin (2x - 1) * (d/dx) (2x -1) = -sin (2x - 1)(2) = -2sin (2x - 1)

8 0
3 years ago
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