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Rom4ik [11]
3 years ago
5

Work out the value of angle x

Mathematics
2 answers:
AleksandrR [38]3 years ago
5 0

Answer:

Its an Isosceles triangle. The two bases are equal

So

x= 180-(62+62)

x=56°.

Dmitry [639]3 years ago
5 0

Answer:

x = 56

Step-by-step explanation:

As you can see two angles are congruent, as the two tally marks suggest so. Therefore not only does the left angle measure 62 but also the right angle does as well. Therefore, further indicating that we are dealing with an isosceles triangle in this scenario. So you would come up with the equation 62(2) + x = 180 because all the angles together add up to get you 180 degrees. So once you say 62 times 2 to get 124 you would subtract that by 180; giving you 56 degrees for x.

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At a local preschool, there is a ratio of three boys two every four girls. If there are 245 total preschoolers enrolled , Then h
White raven [17]

A ratio can be written in three different ways: 3 to 4, 3:4, and 3/4

What does this mean? It means that for every group of 7 students (3+4) there are 3 boys and 4 girls. And how many groups do we have? We have:

245/7= 35 We have 35 groups, and we just said that each group has 3 boys and 4 girls:

35*3= 105 boys

35*4= 140 girls

_ _ _---------

5 0
3 years ago
Let the (x; y) coordinates represent locations on the ground. The height h of
grigory [225]

The critical points of <em>h(x,y)</em> occur wherever its partial derivatives h_x and h_y vanish simultaneously. We have

h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5

Substitute <em>y</em> in the second equation and solve for <em>x</em>, then for <em>y</em> :

2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}

This is to say there are two critical points,

(x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)

To classify these critical points, we carry out the second partial derivative test. <em>h(x,y)</em> has Hessian

H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}

whose determinant is 192y-16. Now,

• if the Hessian determinant is negative at a given critical point, then you have a saddle point

• if both the determinant and h_{xx} are positive at the point, then it's a local minimum

• if the determinant is positive and h_{xx} is negative, then it's a local maximum

• otherwise the test fails

We have

\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0

while

\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0

So, we end up with

h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}

7 0
3 years ago
What is a reasonable customary unit for the capacity of a bottle of water?
Katyanochek1 [597]
A fluid ounce is a customary unit for measuring liquid capacity.
7 0
2 years ago
Read 2 more answers
Hey guys help my please !!Q 4,6,7
padilas [110]
Q4, 4y²=60
y=√15 ( i am not sure)
q6, (5+y) ²=81
5+y=9
y=4
q7 (x+4) (x) =77
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(x+11) (x-7) =0
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6 0
3 years ago
What is the sum of the matrices below ?
Vanyuwa [196]

Answer:

\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]

Step-by-step explanation:

To add two matrices you just need to add the corresponding entries together. In this case, we have that:

\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right]=\left[\begin{array}{ccc}4-8&19+7&-5 + 0\\7-1&0+17&-14+6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]

Then, we conclude that the sume of the two matrices is:

\left[\begin{array}{ccc}4&19&-5\\7&0&-14\end{array}\right] + \left[\begin{array}{ccc}-8&7&0\\-1&17&6\end{array}\right] = \left[\begin{array}{ccc}-4&26&-5\\6&17&-8\end{array}\right]

3 0
3 years ago
Read 2 more answers
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