Solutions
1) <span>Add the whole numbers first ( 7 and 2 )
</span><span>9+<span>7/8</span>+<span>11/12
2) </span></span>Find the Least Common Denominator (LCD) of
<span><span>7 / 8</span>,<span>11 / 12
</span></span>
Start by Listing Multiples
List out all multiples of each denominator, and find the first common one.
8 : <span><span>8,16,24</span>
</span>
12 : <span>12,24
</span>
Therefore, the LCD is <span>24
</span>Method 2: By Prime Factors
List all prime factors of each denominator, and find the union of these primes.
8 : <span>2,2,2
</span>
12 : <span>2,2,3
</span>
Therefore, the LCD is <span>2×2×2×3=24
3) </span>Make the denominators the same as the LCD
<span>9+<span><span>7×3 / </span><span>8×3</span></span>+<span><span>11×2 / </span><span>12×2
</span></span></span>4) Simplify. Denominators are now the same
<span>9+<span>21 / 24</span>+<span>22 / 24
5) J</span></span>oin the denominators
<span>9+<span><span>21+22 / </span>24</span></span>
6) Simplify
<span>9+<span>43 / 24
7) </span></span>Convert 43 / 24 <span>to mixed fraction
</span><span>9+1 <span>19 / 24
8) </span></span>Simplify
<span><span>10 <span>19 / 24</span></span></span>
Answer:
(5x + 6) (x + 7)
Step By Step Explanation:
Use the sum form to the product.
5
<span>So we want to know the new coordinates for the vertex A'(x,y) if we know that the vertex A is at A(-1,2) and vertex B is at B(1,5) and that the triangle ABC is translated 6 units up and 3 units left. So the method is simply to add units 6 to x and 3 to y of A to get A'. Going left means we need to go to negative x direction and going up means we need to go to positive y direction. So: A'(-1-3,2+6) and that is: A'(-4,8). </span>
Answer:
3/2 (decimals): 1.5
Step-by-step explanation:
1. 5(2d+4)=35 -> multiply 5 to (2d+4)
2. 10d + 20 = 35
3. Subtract 20 by both sides
10d = 35-20
10d = 15
4. divide 10 by both sides
d = 15/10
d = 3/2
Answer:
A(0, 2), C(-1, 2), E(-4, -1)
Step-by-step explanation:
It can be useful to graph the equations and plot the points. Only the points in the doubly-shaded area are solutions to the system of inequalities.
You can try the offered points and see which work.
<u>y > 2x +1</u>
A. 2 > 2·0 +1 . . . true
B. 3 > 2·1 +1 . . . . False
C. 2 > 2(-1) +1 . . . true
D. 1 > 2·1 +1 . . . . False
E. -1 > 2(-4) +1 . . . true
F. 0 > 2·0 +1 . . . . False
__
<u>y < -2x +3</u>
A. 2 < -2·0 +3 . . . true
C. 2 < -2(-1) +3 . . . true
E. -1 < -2(-4) +3 . . . true
Points A, C, E are in the solution set.
